嗨，这只是一个简单的计算器。在我问他们是否想要进行另一次转换后，我想允许用户输入“N”或“n”。 （输入Y进行另一次转换/输入N返回主菜单）。我该怎么做？
static int LengthCalculator() {
int LengthCalculatorOption;
string AnotherConversion = null;
double Centimetres = 0.0, Feet = 0.0, Inches = 0.0, TotalInches = 0.0;
const double CENTIMETRES_PER_INCH = 2.54, INCHES_PER_FOOT = 12;
do {
LengthCalculatorMenu();
LengthCalculatorOption = ValidLengthCalculatorReadOption();
if (LengthCalculatorOption == 1) {
Console.WriteLine("Please Enter the Centimetres(cm) that you wish to convert to feet and inches:");
Centimetres = double.Parse(Console.ReadLine());
TotalInches = (Centimetres / CENTIMETRES_PER_INCH); // This will take a floor function of Centimetres/2.54
Feet = (TotalInches - TotalInches % INCHES_PER_FOOT) / INCHES_PER_FOOT; // This will make it divisible by 12
Inches = TotalInches % INCHES_PER_FOOT; // This will give you the remainder after you divide by 12
Console.WriteLine("\nThe equivalent in feet and inches is {0} ft {1} ins", Feet, Inches);
Console.Write("\nWould you like to make an another conversion? \n\n(Enter Y to make an another conversion/Enter any key return to Main menu):");
AnotherConversion = Console.ReadLine();
} else if (LengthCalculatorOption == 2) {
Console.WriteLine("Please Enter the Feet:");
Feet = double.Parse(Console.ReadLine());
Console.WriteLine("Please Enter the Inches:");
Inches = double.Parse(Console.ReadLine());
Centimetres = ((Feet * INCHES_PER_FOOT) + Inches) * CENTIMETRES_PER_INCH;
Console.WriteLine("\nThe equivalent in centimetres is {0}cm", Centimetres);
Console.Write("\nWould you like to make an another conversion? \n\n(Enter Y to make an another conversion/Enter any key return to Main menu):");
AnotherConversion = Console.ReadLine();
}
} while (AnotherConversion == "y" || AnotherConversion == "Y");
return LengthCalculatorOption;
}//End LenthCalculator
static void LengthCalculatorMenu() {
string LengthCalculatorMenu = ("Enter 1) Convert Centimetres to Feet and Inches:"
+ "\nEnter 2) Convert feet and inches to centimetres:");
Console.WriteLine(LengthCalculatorMenu);
} // End LengthCalculatorMenu
static int ValidLengthCalculatorReadOption() {
int LengthCalculatorOption;
bool ValidLengthCalculatorOption = false;
do {
LengthCalculatorOption = int.Parse(Console.ReadLine());
if ((LengthCalculatorOption >= 1) && (LengthCalculatorOption <= 2)) {
ValidLengthCalculatorOption = true;
} else {
ValidLengthCalculatorOption = false;
} // end if
if (!ValidLengthCalculatorOption) {
Console.WriteLine("\n\t Option must be 1 or 2, Please Re-Enter your Option");
LengthCalculatorMenu();
} //end if
} while (!ValidLengthCalculatorOption);
return LengthCalculatorOption;
}// End LengthCalculatorReadOption
static int ReadMainMenuOption() {
int option = 0;
bool ValidMainMenuOption = false;
do {
option = int.Parse(Console.ReadLine());
if ((option >= 1) && (option <= 5)) {
ValidMainMenuOption = true;
} else {
ValidMainMenuOption = false;
} // end if
if (option == 1) {
LengthCalculator();
} else if (option == 2) {
} else if (option == 3) {
} else if (option == 4) {
} else if (option == 5) {
} // end if
if (!ValidMainMenuOption) {
Console.WriteLine("\n\t\a Option must be 1,2,3,4 or 5");
DisplayMenu();
} //end if
} while (!ValidMainMenuOption);
return option;
} //end ReadOption
/* Displays Main Menu
* Precondition:true
* postcondition: DisplayMenu displayed
*/
static void DisplayMenu() {
string mainMenu = "\n1)Length Calculator"
+ "\n2)Body Mass Index Calculator"
+ "\n3)Waist to Height Calculator"
+ "\n4)Fuel Consumption Calculator"
+ "\n5)Exit the Calculator"
+ "\n\nEnter your option(1,2,3,4 or 5 to exit):";
Console.Write(mainMenu);
} //end DisplayMenu
static void Main(string[] args) {
const int Exit = 5;
int menuOption;
do {
DisplayMenu();
menuOption = ReadMainMenuOption();
} while (menuOption != Exit);
Console.Write("Thank you for using this Calculator. Press any Key to Exit");
//terminating message
Console.ReadKey();
}//end Main
答案 0 :(得分：1)
您可以创建一个处理用户输入的单独方法。例如，此方法将确定用户是否输入了Y或N.如果他们没有重新提示他们这样做：
static bool AnotherConversion()
{
var prompt = "\nWould you like to make an another conversion? \n\n(Enter (Y) to make another conversion or (N) to return to the Main Menu):";
Console.WriteLine(prompt);
while (true)
{
var userInput = Console.ReadLine();
if (String.Compare("Y", userInput, StringComparison.Ordinal)
{
return true;
}
else if (String.Compare("N", userInput, StringComparison.Ordinal)
{
return false;
}
else
{
// Invlalid input, re-prompt
Console.WriteLine("Invalid Input, please enter or (Y) or (N)!");
Console.WriteLine(prompt);
}
}
}
您可以简单地更新do / while循环，以便条件基于AnotherConversion方法。这将允许在计算完成时询问提示：
static int LengthCalculator() {
....
do {
.....
} while (AnotherConversion());
return LengthCalculatorOption;
}//End LenthCalculator
答案 1 :(得分：0)
在您想要的地方调用此方法：
static bool shouldMakeAnotherConversion()
{
repeatQuestion:
// This shows the question to the user
Console.Write("Do you want to make another conversion (Y/N)? ");
ConsoleKeyInfo answer = Console.ReadKey(true);
switch (answer.Key)
{
case ConsoleKey.Y: return true;
case ConsoleKey.N: return false;
}
//If the user types any other key, the program will repeat the question
Console.WriteLine();
goto repeatQuestion;
}
答案 2 :(得分：0)
class Program
{
public static void parameter(int num1, int num2, out int add, out int sub, out int mul, out float div)
{
add = num1 + num2;
sub = num1 - num2;
mul = num1 * num2;
div = (float)num1 / num2;
}
static void Main(string[] args)
{
int num1, num2;
int add, sub, mul;
float div;
Console.Write("Enter 1st number\t");
num1 = Convert.ToInt32(Console.ReadLine());
Console.Write("\nEnter 2nd number\t");
num2 = Convert.ToInt32(Console.ReadLine());
Program.parameter(num1, num2, out add, out sub, out mul, out div);
Console.WriteLine("\n\n{0} + {1} = {2}", num1, num2, add);
Console.WriteLine("{0} - {1} = {2}", num1, num2, sub);
Console.WriteLine("{0} * {1} = {2}", num1, num2, mul);
Console.WriteLine("{0} / {1} = {2}", num1, num2, div);
Console.ReadLine();
}
}
}
答案 3 :(得分：0)
namespace ConsoleApplication2
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Type you first number :");
Console.WriteLine("Type you second number :");
Console.WriteLine("Enter the operation + (addition), - (soustraction), * (multiplication), / (division)");
string stringOperation = Console.ReadLine();
switch (operation)
{
case 1:
result = firstNumber + secondNumber;
break;
case 2:
result = firstNumber - secondNumber;
break;
case 3:
result = firstNumber * secondNumber;
break;
case 4:
result = firstNumber / secondNumber;
break;
}
}
}
}