Question

我正在尝试编写一个php论坛的OOP风格，我有一个难度，这是我第一次编写OOP样式并且我一直收到错误

第5行出乎意料的T_VARIABLE

这是我的代码

<?php
class dbManager{
  var $MySQL_Conx;
  var $details = configManager::getConfig;
  var $mysqli = $this->dbConnect();
  public function dbSelect($sql, $mysqli){

  }
  private function dbConnect(){
    $this->CloseConnection()
    $this->MySQL_Conx = mysqli_connect($this->details['dbhost'], $this->details['dbuser'], $this->details['dbpass'], $this->details['dbdatabase'])
    if (mysqli_connect_errno()){
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
      exit();
    } else {
      return $MySQL_Conx;
    }
  }
}
?>

同样configManager::getConfig;返回一组包含连接数据库的所有细节。

Answer 1

您需要在constructor上进行初始化。代码中的注释表明您所犯的错误。

来自PHP手册

这个声明可能包括初始化，但是这个初始化必须是一个常量值 - 也就是说，它必须能够在编译时进行评估，不得依赖于运行时信息以便进行评估。

固定代码......

<?php
class dbManager{
    var $MySQL_Conx;
    var $details; 
    var $mysqli; 

    function __construct()   //<---- Wrapped them in a constructor
    {
        $this->details=configManager::getConfig;
        $this->mysqli=$this->dbConnect();
    }

    public function dbSelect($sql, $mysqli){

    }
    private function dbConnect(){
        $this->CloseConnection();   //<--- You forgot a semicolon
    $this->MySQL_Conx = mysqli_connect($this->details['dbhost'], $this->details['dbuser'], $this->details['dbpass'], $this->details['dbdatabase']);
    if (mysqli_connect_errno()){
        echo "Failed to connect to MySQL: " . mysqli_connect_error();
        exit();
    } else {
        return $this->MySQL_Conx; //<---- Added this keyword
    }
  }
}
?>

Answer 2

请在构造函数

中指定值

<?php
class dbManager{
  var $MySQL_Conx;
  var $details = array();
  var $mysqli = '';
  //you have to assign the values in the constructor
  public function __construct()
  {
    //assign the details
    $this->details = configManager::getConfig;
    //assign the mysql connection
    $this->mysqli = $this->dbConnect()
  }

  public function dbSelect($sql, $mysqli){

  }
  private function dbConnect(){
    $this->CloseConnection()
    $this->MySQL_Conx = mysqli_connect($this->details['dbhost'], $this->details['dbuser'], $this->details['dbpass'], $this->details['dbdatabase']);
    if (mysqli_connect_errno()){
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
      exit();
    } else {
      return $MySQL_Conx;
    }
  }
}

dbManager类返回意外的T_VARIABLE

2 个答案:

固定代码......