Question

好的，所以我需要从表单中检索我的变量并将它们放在insert语句中我可以将它们输入数据库。问题似乎是从我检索它们的地方如果我以它的形式对它们进行硬编码，那么数据库或连接就没有问题，只有检索价格和isbn如下所示。

 <?php session_start();
 session_regenerate_id();
 ($_SESSION['count']) ? $_SESSION['count']++ : $_SESSION['count'] = 1;



?>

<!-- example for PHP 5.0.0 final release -->

<html>

 <head>
  <title>Session running</title>
 </head>

 <body>
 <h1> Book Details</h1>
 <a href="catalog.php?<?php echo( SID ); ?>">Go Back To Inventory</a>
 <hr>
 PHPSESSID = <?php echo session_id(); ?>
 <br>
 You have been here <?php echo( $_SESSION['count'] ); ?> times in this session
 <hr>


<html>
<head>
<title>Count Visits</title>
</head>

<body>
<h2></h2>

</body>
</html>



<?php require_once("Include/db_connect.php");

if (isset($_REQUEST['button'])) // submit was clicked
{

display_output_page();
}

?>
<?php






    $db_link = db_connect("project");



    $self = $_SERVER['PHP_SELF'];

if (isset($_REQUEST['submit'])) // submit was clicked
{

      display_output_page();
   }


?>









<?php


    $isbn = $_REQUEST['isbn'];
    $price = isset($_REQUEST['price']) ? $_REQUEST['price'] : '';
    $quantity = isset($_REQUEST['value']) ? $_REQUEST['value'] : '';












$fields = mysql_list_fields("project", "books");
$num_columns = mysql_num_fields($fields);


$query = "SELECT * FROM books WHERE isbn=".$isbn.";";
$result = mysql_query($query) or die("SQL failed");




echo '<table border="1">';



echo "<tr>";
for ($i = 0; $i < $num_columns; $i++)
{
   echo "<th>", mysql_field_name($fields, $i), "</th>";


}
  echo "<th> Quantity </th>";
    echo "<th> Add </th>";
echo "</tr>";


while ($row = mysql_fetch_assoc($result))
{



        echo "<tr>";
        echo "<td>".$row['isbn']."</td>";
        echo "<td>".$row['title']."</td>";
        echo "<td>".$row['author']. "</td>";
        echo "<td>".$row['pub']."</td>";
        echo "<td>".$row['year']."</td>";
        echo "<td>".$row['price']."</td>";
        echo "<td><img src='images/".$row['image']."'></td>";


//IN HERE IS THE PROBLEM, RETRIEVING THE isbn and price variables wont work



        echo '<form action="" method="POST">
    <td><input type = "text" value=1 style="width: 30px;" name =   "value"/></td>
    <input type="hidden" name="isbn"  value="<php echo $isbn ?>">
    input type="hidden" name="price"  value="<?php echo $price ?>">
    <td><input type = "submit" name = "button" value = "Add"></td>

                </form>

    ';



        echo "</tr>";








}
echo "</table>";





mysql_free_result($result);
mysql_close($db_link);
?>


<?php
function display_output_page()
{


 require_once("Include/db_connect.php");
 $db_link = db_connect("project");


//This is where i need to retrieve the isbn and price variables for my SQL insert

    $sessionID = session_id();
    $isbn = $_REQUEST['isbn'];
    $price = $_REQUEST['price'];
    $quantity =$_REQUEST['value'];


 $db_link = db_connect("project");
 $sql2 = "INSERT INTO cart(sessionID,isbn,quantity,price)
 VALUES('$sessionID','$isbn','$quantity','$price')";


 $result2 = mysql_query($sql2) or die ("<br> Could not execute SQL query");

 if($result2)
{

echo "You Have Added The Item To The Cart";

}


mysql_close($db_link);

}
?>

Answer 1

您缺少一些基本的语法元素。

<input type="hidden" name="isbn"  value="<?php echo $isbn; ?>">
<input type="hidden" name="price"  value="<?php echo $price; ?>">

另外，我建议您阅读有关基于PHP HTML表单处理的内容，因为您的代码中存在许多小错误。

http://www.w3schools.com/php/php_forms.asp

无法从HTML表单中检索值对于PHP

1 个答案: