Question

如何获得谷歌api的10个搜索结果，我有一个代码，但它只显示4个搜索结果

$query = 'akon';
$url = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=".$query;

$body = file_get_contents($url);
$json = json_decode($body);

for($x=0;$x<count($json->responseData->results);$x++){
echo "<b>Result ".($x+1)."</b>";
echo "<br>URL: ";
echo $json->responseData->results[$x]->url;
echo "<br>VisibleURL: ";
echo $json->responseData->results[$x]->visibleUrl;
echo "<br>Title: ";
echo $json->responseData->results[$x]->title;
echo "<br>Content: ";
echo $json->responseData->results[$x]->content;
echo "<br><br>";
}

Answer 1

可以从此api获得的最大结果数为8.您可以通过添加＆＃34;＆amp; rsz = large＆＃34;来实现。到你的网址如下。

$ url =＆＃34; http://ajax.googleapis.com/ajax/services/search/web?v=1.0 ＆amp; rsz = large ＆amp; q =＆＃34;。$ query;

要获得8个以上的结果，您需要通过添加另一个名为＆＃34; start＆＃34;的参数来执行上述操作两次。这是基于零指数的。因此，对于结果的第一页，$ url必须是

$ url =＆＃34; http://ajax.googleapis.com/ajax/services/search/web?v=1.0 ＆amp; rsz = large＆amp; start = 0 ＆amp; q =＆＃34;。$ query;

对于第二页，

$ url =＆＃34; http://ajax.googleapis.com/ajax/services/search/web?v=1.0 ＆amp; rsz = large＆amp; start = 8 ＆amp; q =＆＃34;。$ query;

如何获得谷歌api 10搜索结果

1 个答案: