来自php MySQL查询的JSON显示不存在的列

Question

好吧，我所拥有的是一个非常简单的XAMPP设置，其中包含一个包含两行的单个表的数据库。我有一个PHP脚本随机抓取其中一行，然后在JSON中打印生成的查询。无论出于何种原因，虽然JSON有＆＃39;列＆＃39; （并不是真的想把它们称为列，因为JSON不能列，但是，是的......）实际上并不存在于表中。

我对XAMPP堆栈中的所有内容都很陌生，所以如果这是一个愚蠢的问题，我会提前道歉。

这是我的表：

以下是生成的JSON：

{"0":"1","id":"0.9645465863538408","1":"Big Mac","name":"Big Mac","2":"A double layer of sear-sizzled 100% pure beef mingled with special sauce on a sesame seed bun and topped with melty American cheese, crisp lettuce, minced onions and tangy pickles.","description":"A double layer of sear-sizzled 100% pure beef mingled with special sauce on a sesame seed bun and topped with melty American cheese, crisp lettuce, minced onions and tangy pickles.","3":"http:\/\/www.mcdonalds.com\/content\/dam\/McDonalds\/item\/mcdonalds-Big-Mac.png","imgSrc":"http:\/\/www.mcdonalds.com\/content\/dam\/McDonalds\/item\/mcdonalds-Big-Mac.png","4":"2","upVotes":"2","5":"1","downVotes":"1","6":"0.9645465863538408"} 

（＆＃34; 0＆＃34;，＆＃34; 1＆＃34;等等不存在于表格中）

这是我的php：

$password = "";
$usertable = "mcdonalds"; 

//Connect
mysql_connect($hostname, $username, $password) OR DIE ("Unable to 
connect to $hostname . Please try again later.");
mysql_select_db($dbname);

//Fetch
$query = "SELECT * FROM `McDonalds`AS r1 JOIN(SELECT (RAND() *(SELECT MAX(id) FROM `McDonalds`)) AS id) AS r2 WHERE r1.id >= r2.id  ORDER BY r1.id ASC LIMIT 1";
$result = mysql_query($query);

$row = mysql_fetch_array($result);  
//Print
echo json_encode($row);

Answer 1

使用mysql_fetch_assoc代替mysql_fetch_array。默认情况下，mysql_fetch_array返回一个数组，其中包含每列的命名和数字索引。

或者您可以使用mysql_fetch_array($result, MYSQL_ASSOC)。默认的第二个参数是MYSQL_BOTH，这会导致您看到的结果。