Question

我是Android新手，并尝试使用一些时间计数器在几秒钟后自动关闭我的膨胀弹出窗口。我不知道如何计算计时器（5秒）。

  LayoutInflater inflater = (LayoutInflater)screen.getSystemService(screen.LAYOUT_INFLATER_SERVICE);
                    layout =  inflater.inflate(R.layout.log_viewer,null);

                    AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
                    builder.setCancelable(true);
                    builder.setView(layout);

                    AlertDialog alertDialog = builder.create(); 
                    alertDialog.show();

                    Button btn0= (Button)layout.findViewById(R.id.btn0);
                    Button btn1= (Button)layout.findViewById(R.id.btn1);
                    Button btn2= (Button)layout.findViewById(R.id.btn2);
                    btn0.setOnClickListener(new OnClickListener() {

                        @Override
                        public void onClick(View v) {

                            Intent i =new Intent(Main_Activity.this,Act.class);
                            startActivity(i);
                            overridePendingTransition(R.anim.animation,R.anim.animation2);
                        }
                    });  
                    btn1.setOnClickListener(new OnClickListener() {

                        @Override
                        public void onClick(View v) {

                            Intent i =new Intent(Main_Activity.this,Activity2.class);
                            startActivity(i);
                            overridePendingTransition(R.anim.animation,R.anim.animation2);
                        }
                    });  
                    btn2.setOnClickListener(new OnClickListener() {

                        @Override
                        public void onClick(View v) {

                            Intent i =new Intent(Main_Activity.this,Activity1.class);
                            startActivity(i);
                            overridePendingTransition(R.anim.animation,R.anim.animation2);
                        }
                    });  


                    WindowManager.LayoutParams lp = new WindowManager.LayoutParams();
                    Window window = alertDialog.getWindow();
                    lp.copyFrom(window.getAttributes());

                    lp.width = WindowManager.LayoutParams.MATCH_PARENT;
                    lp.height = WindowManager.LayoutParams.WRAP_CONTENT;
                    window.setAttributes(lp);

Answer 1

你可以像 -

那样关闭它

new Handler().postDelayed(new Runnable(){
    public void run() {
        popup.dismiss();                    
            }                   
}, 5 *1000);

Answer 2

卡纳克索尼的方法很好，但可能会引起一些问题。如果在显示弹出窗口时离开活动，则可能会导致异常。你应该在活动中的onDestroy（）方法中添加一个dismiss，如下所示。

public void destroy(){
    if (popup != null) {
        popup.dismiss();
        popup = null;
    }
}

并在处理程序中：

new Handler().postDelayed(new Runnable(){
public void run() {
    if (popup != null) {
        popup.dismiss();
        popup = null;
    }                    
        }}, 5 *1000);

希望对你有所帮助。

一段时间后AutoClose弹出窗口

2 个答案: