长话短说,我在大学Comp Sci课上,教授希望我们从头开始构建一个Vector。他们在网上有什么好的教程吗?我做了谷歌搜索但没有真正出现过。
修改
根据文件老师发出的载体需要能够做到以下几点:
此外,该课程需要克隆Cloneable并自我扩展。
这是我到目前为止所提出的:
package collection;
public class MyVector implements Cloneable {
protected Object[] items;
protected int arraySize;
protected int maxCap;
public MyVector (int initialCapacity) {
super();
if (initialCapacity < 0) {
throw new IllegalArgumentException("Illegal Capacity: "+ initialCapacity);
}
this.items = new Object[initialCapacity];
this.arraySize = 0;
this.maxCap = initialCapacity;
}
public MyVector() {
this(10);
}
public void append(Object element) {
int newArraySize = this.arraySize + 1;
if(this.maxCap == newArraySize) {
this.items = this.increaseCap(newArraySize);
this.items[this.arraySize] = element;
this.arraySize += 1;
//System.out.println(this.items[this.arraySize);
} else {
this.items[this.arraySize] = element;
this.arraySize +=1;
}
}
@Override
public String toString() {
String output = "[";
//output = this.items[0].toString();
for(int i = 0; i < this.arraySize; i++) {
output += this.items[i] + ", ";
}
output += "]";
return output;
}
public void clear() {
for(int i = 0; i < this.arraySize; i++) {
this.items[i] = null;
this.arraySize = 0;
}
}
public boolean contains(Object element) {
boolean doesContain = false;
for(int i = 0; i < this.arraySize; i++) {
if(element == this.items[i]) {
doesContain = true;
i = this.arraySize;
}
}
return doesContain;
}
public Object elementAt(int index) {
if(this.arraySize >= index) {
return this.items[index];
} else {
Object temp = null;
System.out.println("No index of " + index);
return temp;
}
}
public Object indexOf(Object element) {
Object index = "No value found";
for(int i = 0; i < this.arraySize; i++) {
if(element == this.items[i]) {
index = i;
break;
}
}
return index;
}
public boolean isEmpty() {
if(this.arraySize == 0) {
return true;
}
return false;
}
public void replace(int index, Object element) {
if(this.arraySize > index) {
this.items[index] = element;
} else {
System.out.println("No element at " + index);
}
}
public int size() {
return this.arraySize;
}
public void reverse() {
Object[] temp = new Object[this.items.length];
int j = this.arraySize;
for(int i = 0; i < this.arraySize; i++) {
temp[j] = this.items[i];
j--;
}
this.items = temp;
}
public void ensureCapacity(int minCapacity) {
if(minCapacity > this.items.length) {
this.items = this.increaseCap(minCapacity);
}
}
public Object[] increaseCap(int minCap) {
Object[] arr1 = new Object[minCap * 2];
for(int i = 0; i < minCap; i++) {
arr1[i] = this.items[i];
}
this.maxCap = this.maxCap * 2;
return arr1;
}
@Override
public Object clone() {
return this.items;
}
public boolean checkIndex(int index) {
boolean check = false;
if(index < this.arraySize) {
check = true;
}
return check;
}
public void removeAt(int index) {
if(true == this.checkIndex(index)) {
Object[] temp = new Object[this.arraySize - 1];
for(int j = 0; j < index; j++) {
temp[j] = this.items[j];
}
for(int j = index + 1; j < this.arraySize; j++) {
temp[j-1] = this.items[j];
}
this.items = temp;
this.arraySize = this.arraySize - 1;
}
}
public void insertAt(int index, Object element) {
if (this.checkIndex(index) == true) {
Object[] temp = new Object[this.arraySize];
for(int i = index; i < this.arraySize; i++) {
temp[i+1] = this.items[i];
}
this.items[index] = element;
for (int i = index + 1; i < this.arraySize; i++) {
this.items[i] = temp[i - 1];
}
this.arraySize = this.arraySize - 1;
}
}
public void remove(Object element) {
for(int i = 0; i < this.items.length; i++) {
if(this.items[i] == element) {
this.removeAt(i);
}
}
}
public void removeRange(int fromIndex, int toIndex) {
for(int i = fromIndex; i < toIndex; i++) {
this.removeAt(i);
}
}
public void merge(MyVector vector2) {
this.ensureCapacity(vector2.size() + this.arraySize);
for(int i = 0; i < vector2.size(); i++) {
this.append(vector2);
}
}
}
答案 0 :(得分:1)
假设您的作业正在复制java.util.Vector
,我会看一下Vector是什么来复制它:
向量实现 动态数组 。它类似于 ArrayList ,但是 有两点不同:
Vector 已同步 。
- 醇>
Vector包含许多不属于集合框架的 遗留方法 。
你可以尝试以同步的方式使用ArrayList来复制Vector,但我确信有更好的解决方案。