Question

我正在尝试构建一个Oracle SQL查询，当计数大于1时，它会按行分组以及组成该组的行。请参阅下面的示例和SQL查询分组。任何帮助或建议将不胜感激。

例如，使用以下数据集 -

======================
 ID | NAME |  AUTHOR
======================
 2  | Abc  | John 
 6  | Abc  | John 
 3  | Xyz  | Mike 
 4  | Abc  | Mike 
 5  | Xyz  | John 
 1  | Abc  | Mike 
 7  | PQR  | Raj 


Expected Result - 
===========================
ID | NAME | AUTHOR | COUNT
===========================
   | Abc  |        |  4
2  | Abc  |  John  |    
6  | Abc  |  John  |    
4  | Abc  |  Mike  |    
1  | Abc  |  Mike  |    
   | PQR  |        |  1
   | Xyz  |        |  2
3  | Xyz  |  Mike  |    
5  | Xyz  |  John  |    


SELECT  NAME, COUNT(NAME) from (
SELECT 2 as ID, ' Abc  ' as NAME, ' John ' as AUTHOR FROM DUAL
UNION 
SELECT 6 as ID, ' Abc  ' as NAME, ' John ' as AUTHOR FROM DUAL
UNION
SELECT 3 as ID, ' Xyz  ' as NAME, ' Mike ' as AUTHOR FROM DUAL
UNION
SELECT 4 as ID, ' Abc  ' as NAME, ' Mike ' as AUTHOR FROM DUAL
UNION
SELECT 5 as ID, ' Xyz  ' as NAME, ' John ' as AUTHOR FROM DUAL
UNION
SELECT 1 as ID, ' Abc  ' as NAME, ' Mike ' as AUTHOR FROM DUAL
UNION
SELECT 7 as ID, ' PQR  ' as NAME, ' Raj ' as AUTHOR FROM DUAL)
GROUP BY NAME
ORDER by NAME;

Answer 1

SQL> with t as (
  2  SELECT 2 as ID, ' Abc  ' as NAME, ' John ' as AUTHOR FROM DUAL
  3  UNION
  4  SELECT 6 as ID, ' Abc  ' as NAME, ' John ' as AUTHOR FROM DUAL
  5  UNION
  6  SELECT 3 as ID, ' Xyz  ' as NAME, ' Mike ' as AUTHOR FROM DUAL
  7  UNION
  8  SELECT 4 as ID, ' Abc  ' as NAME, ' Mike ' as AUTHOR FROM DUAL
  9  UNION
 10  SELECT 5 as ID, ' Xyz  ' as NAME, ' John ' as AUTHOR FROM DUAL
 11  UNION
 12  SELECT 1 as ID, ' Abc  ' as NAME, ' Mike ' as AUTHOR FROM DUAL
 13  UNION
 14  SELECT 7 as ID, ' PQR  ' as NAME, ' Raj ' as AUTHOR FROM DUAL)
 15  select id, name, author, count#
 16  from (
 17  select t.id, t.name, t.author, decode(grouping(id),1,count(*),null) count#,
 18  count(*) over (partition by name) cn, grouping(id) gid
 19  from t
 20  group by grouping sets((id,name,author),(name))
 21  )
 22  where (cn != 2 or count# is not null)
 23  order by name, gid desc, author
 24  /

        ID NAME   AUTHOR     COUNT#                                             
---------- ------ ------ ----------                                             
            Abc                   4                                             
         2  Abc    John                                                         
         6  Abc    John                                                         
         4  Abc    Mike                                                         
         1  Abc    Mike                                                         
            PQR                   1                                             
            Xyz                   2                                             
         5  Xyz    John                                                         
         3  Xyz    Mike

Answer 2

select
    id, name, author, decode(grouping_id(id, name), 2, count(*)) count
from
    books
group by
    rollup(name, (author, id))
having
    grouping_id(id, name) != 3
order
    by name, id nulls first

Answer 3

按名称分组的数据与作者的数量：

SELECT NULL id, name, NULL author, count(author) "count"
FROM myTable
GROUP BY name

当有多位作者时加上细节：

SELECT id, name, author, NULL "count"
FROM mytable
WHERE name NOT IN (SELECT name FROM myTable GROUP BY name HAVING count(1) = 1)

将这些与一些订单放在一起以获得想要的结果

SELECT id, name, author, NULL "count"
FROM mytable
WHERE name NOT IN (SELECT name FROM myTable GROUP BY name HAVING count(1) = 1)
UNION ALL
SELECT NULL id, name, NULL author, count(author) "count"
FROM myTable
GROUP BY name
ORDER BY 2, 4, 1, 3

Oracle SQL - 组和详细记录

3 个答案: