如何获得具有更好性能的重复值的行

Question

我需要获取列中具有重复值的行。这是SQL：

select * from `match` where `match`.`homeTeam` in 
(select `matchView`.`homeTeam` from `matchView` 
group by `matchView`.`homeTeam` having (count(0) > 1))
 order by `match`.`homeTeam`

它完成了这项工作，但需要15秒。我该怎么做才能提高速度

编辑：解释sql结果：

id  select_type     table   type    possible_keys   key     key_len     ref     rows    Extra   
1   PRIMARY     match   ALL     NULL    NULL    NULL    NULL    2691    Using where; Using filesort
2   DEPENDENT SUBQUERY  match   ALL     NULL    NULL    NULL    NULL    2691    Using where; Using temporary; Using filesort

Answer 1

select `match`.* 
from `match` join (select `matchView`.`homeTeam` 
                   from `matchView` 
                   group by `matchView`.`homeTeam` 
                    having (count(0) > 1)) watches ON `match`.`homeTeam`=watches.`homeTeam`
order by `match`.`homeTeam`