我想获得特定的子节点(即类名)。我怎样才能做到这一点。这是我的代码
<div id="mess">
<h1>Bhashyam School</h1>
<p>AC Nagar Main Road, Nellore <br/>Ho, Nellore - 524001 </p>
<p class="tel">Telephone: +(91)-9603444376 </p>
<p class="email">Email: <a href="mailto:info@citydeal.in">info@citydeal.in</a></p>
<p class="web">Website: <a href="http//citydeal.in" target="new">http//citydeal.in</a></p>
<p class="description">Hours of Operation :
Monday, Tuesday, Wednesday, Thursday, Friday, Saturday: 09:30 am to 10:00 pm<br>
Sunday: Closed , Modes of Payment :
Cash
</p>
<form name="contactform" method="post" action="send.php" onsubmit="return getChilds();">
<p>
<input id="box" type="text" name="telephone" placeholder="Enter Mobile Number"/>
<input type="hidden" name="strToSend" id="strToSend"/>
<button type="submit" class="button" value="Submit">Get SMS</button>
</p>
</form>
</div>
<script type="text/javascript">
function getChilds()
{
var arr=document.getElementById('mess').childNodes, str='';
for(var i=0; i<arr.length; i++) {
if(arr[i].innerHTML!=undefined) {
str+=" "+(arr[i].textContent||arr[i].innerText);
}
}
document.getElementById("strToSend").value=str;
return true;
}
</script>
在上面的javascript代码中,我希望childNodes具有特定的类名(例如:p class =&#34; tel&#34;,p class =&#34; email&#34;)。
答案 0 :(得分:1)
使用jQuery?
.children(".yourClass")
和正如我在评论中所说的那样,没有jQuery:
.querySelectorAll(".yourClass")
因为我是世界上最好的人,所以这是一个有.querySelectorAll()
的JSFiddle:
(为了让您看到结果,我将您的hidden
输入设为text
)