所以我有两个数组:
1. $users_populated = users_populated: Array
(
[0] => Array
(
[id] => 10000106
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
)
[1] => Array
(
[id] => 10000106
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
[role] =>
[roleids] =>
[platform] =>
)
[2] => Array
(
[id] => 10000065
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
[3] => Array
(
[id] => 296
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
[4] => Array
(
[id] => 297
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
)
2. $user_list: Array
(
[0] => 10000106
[1] => 297
)
所以我想要第一个数组中与第二个数组匹配的值 这是条目:
$output = output: Array
(
[0] => Array
(
[id] => 10000106
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
)
[1] => Array
(
[id] => 297
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
)
来自第一个数组的短ID和第二个数组中的值应匹配
我已经尝试过使用数组交叉键,但这并没有解决..
感谢阅读。
答案 0 :(得分:2)
$result = array_uintersect($one, $two, function($x, $y)
{
$x = is_array($x)?$x['id']:$x;
$y = is_array($y)?$y['id']:$y;
return $x-$y;
});
- 你的第二个数组是普通的,因此它将直接作用于回调。
答案 1 :(得分:0)
如果要检查两个数组是否包含相同的值, 无论价值观如何?订单,你不能使用" =="或" ==="。 试试这个功能。
<?php
function array_equal($a, $b) {
return (is_array($a) && is_array($b) && array_diff($a, $b) === array_diff($b, $a));
}
?>
答案 2 :(得分:0)
通过循环$ users_populated和array_seach函数,您可以获得预期的结果。
<?php
$output = array();
// Case 1: This will overlap by using the last appearance of the same ID value if repeated ID appears in $users_populated
foreach($users_populated as $value) {
if($key = array_search($value['id'], $user_list))
$output[$key] = $value;
}
// Case 2: This will use the first result found in $users_populated
foreach($users_populated as $value) {
if(empty($output[$value['id']]) && $key = array_search($value['id'], $user_list))
$output[$key] = $value;
}
var_dump($output);
希望这就是你想要的。