我目前在文件中有一个整数的arraylist,如下所示。 1,3,4,3,5,6,5,5我已经对整数进行了排序,但正如你所看到的那样,有一些重复的整数。我想知道如何找到最重复的整数然后将其打印出来?
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.Collections;
public class Lab8
{
public static void main(String[] args) throws FileNotFoundException
{
ArrayList<Integer>myInts = new ArrayList<Integer>();
Scanner myFile = new Scanner(new File("numbers.txt"));
while (myFile.hasNextInt())
{
myInts.add(myFile.nextInt());
}
System.out.println(myInts);
Collections.sort(myInts);
System.out.println(myInts);
}
}
答案 0 :(得分:0)
你走了:
int max = 0;
int nextMax = 0;
int maxItem = 0;
for(int i = 0; i < myInts.size(); i++) {
if(i == 0 )
continue;
if(myInts.get(i) == myInts.get(i-1)) {
if(max > nextMax ) {
nextMax = max;
maxItem = myInts.get(i);
}
else {
max++;
nextMax = max;
maxItem = myInts.get(i);
}
} else {
max = 0;
}
}
System.out.println(maxItem);