我有这个数组:
$urls = array(
0 => array('url' => 'phpclasses.org', 'keyword' => 'phpclass'),
1 => array('url' => 'phpclasses.org', 'keyword' => 'php'),
2 => array('url' => 'php.com', 'keyword' => 'php')
);
我的问题是我想将上面的数据替换为我从数据库中获取的数据。
我有一个包含以下字段的表:
id(auto), url and keyword.
然后我连接到数据库:
$con=mysqli_connect("localhost","root","","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM my_table");
我的问题是如何创建一个mysqli查询来获取上面数组格式的数据?
答案 0 :(得分:1)
以下代码复制了您的数组,数组的索引是数据库中的id
字段,其他值在数组内部。
<?php
$con = mysqli_connect("localhost","root","","my_db");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con, "SELECT * FROM my_table");
$urls = array();
while ($row = mysqli_fetch_array($result)) {
$urls[$row['id']] = array('url' => $row['url'], 'keyword' => $row['keyword']);
}
var_dump($urls);
?>
答案 1 :(得分:0)
试试这个
<?php
mysql_connect("localhost", "username", "password");
mysql_select_db("DATABASE");
$urls = array();
$query = mysql_query("SELECT * FROM YOUR_TABLE");
while($row = mysql_fetch_array($query)) {
$urls[] = array('url' => $row['url'], 'keyword' => $row['keyword']);
}
var_dump($urls);
?>
使用您的代码:
<?php
$con=mysqli_connect("localhost","root","","my_db");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM my_table");
$urls = array();
while($row = mysql_fetch_array($result)) {
$urls[] = array('url' => $row['from_id'], 'keyword' => $row['to_id']);
}
var_dump($urls);
?>
如果答案有帮助,请投票。