Question

这是我的登录页面的代码，我收到错误::

 <%
    String uid=request.getParameter("t1");
    String pwd=request.getParameter("t2");
    try
    {
    Class.forName("oracle.jdbc.driver.OracleDriver");
    Connection con=DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:XE","Sindhu","project");
    PreparedStatement pst=con.prepareStatement("select * from Shield where user_id=?",ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_READ_ONLY);
    pst.setString(1,uid);
    ResultSet rs=pst.executeQuery();
    String master=rs.getString(5);
    if(master.equals(pwd))
    {
    session.putValue("userid",uid);
    %>
    -----------html code
          <%
            PreparedStatement pst1=con.prepareStatement("select * from "+uid+"",ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_READ_ONLY);
            ResultSet rset=pst1.executeQuery();
            while(rset.next())
          {
            String sitename=rset.getString(1);
            String username=rset.getString(2);
            String password=rset.getString(3);
            String url1=rset.getString(4);
          %>
           ------html code
    <%
    }
    rset.close();
    pst1.close();
    %>
   ----html code

     <%
    }
    else
    {
    %>
        ----html code
              <%
    }
    rs.close();
    pst.close();
    con.close();
    }
    catch(Exception e)
    {
    out.println(" "+e);
    }
    %>

以下是Oracle中的表创建语法：

CREATE TABLE Shield
(
f_name varchar2(40),
user_id    varchar2(40) PRIMARY KEY,
email   varchar2(40),
phone  Number(11),
pass_id    varchar2(40),
face    varchar2(40),
finger   varchar2(40)
);

我正在使用TOMCAT并且我得到一个异常：java.sql.SQLException：Exhausted Resultset

我甚至尝试使用uid名称在oracle中手动插入几行。所以，rs不会是空的。

提前谢谢，娜斯迪胡

java.sql.SQLException：已用尽的Resultset

0 个答案: