Question

我有一个查询返回一个数组，我在第一个选择中显示它，然后当你点击选项的一个选项时，它返回所选名称的id，所以我在生成最后一个选择时遇到问题第一个Select的匹配，即代码：

<html>
<head>

<script language="javascript" type="text/javascript">

function ajaxFuncio(selectobj){
    var i = selectobj.selectedIndex;
    var idOptionFirst = selectobj[i].getAttribute('id');
    return idOptionFirst;
    //alert(idOptionFirst);
}

function secondSelect(){
    var ajaxRequest; 
    try{
    // Opera 8.0+, Firefox, Safari
        ajaxRequest = new XMLHttpRequest();
    }
    catch (e){
    // Internet Explorer
        try{
            ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
        }
        catch (e){
            try{
                ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
            }
            catch (e){
                alert("En el teu navegador no funciona!");
                return false;
            }
        }
    }

    // Crear una funció que envia dades al servidor 
    //i actualitza la seccio div
    ajaxRequest.onreadystatechange = function(){
        if(ajaxRequest.readyState == 0){
            var ajaxDisplay = document.getElementById('info');
            ajaxDisplay.innerHTML = ajaxRequest.responseText;
            alert("asdf");
        }
    }

    // Agafem els valors passats
    var selectPrimer = document.getElementsByName('selActi');
    var codi = ajaxFuncio(selectPrimer);
    var cadenaconsulta = "?idTActivitat=" + codi ;
    ajaxRequest.open("GET", "test_ajax.php" + cadenaconsulta, true);
    ajaxRequest.send(null); 
}

</script>
</head>
<body>

<?php

$conn=oci_connect('*******','****','****')
    or die("Failed to connect to Oracle: ".mysqli_error());

//PRIMER SELECT
$sqlFirstSel=oci_parse($conn, 'SELECT * FROM ACTIVIDAD');
oci_execute($sqlFirstSel);

$cadena = "<form id='formActis' method='POST' action='test_ajax.php'>";
$cadena .= "<table>";
$cadena .= "    <tr>";
$cadena .= "        <td>";
$cadena .= "            <select name='selActi[]' onChange='ajaxFuncio(this);'>";
$cadena .= "                <option selected>Selecciona l'Activitat:</option>";
$cadena .= "                <option></option>";
while (($row=oci_fetch_array($sqlFirstSel,OCI_BOTH))!=false){
    $cadena.="              <option name='idFirstSel' id='".$row['ID']."'>".$row['NOM']."</option>";
}
$cadena .= "            </select>";
$cadena .= "        </td>";
$cadena .= "        <td>";
$cadena .= "            <input type='button' onclick='secondSelect();' value='enviar'/>";
$cadena .= "        </td>";
$cadena .= "    </tr>";
$cadena .= "</table>";

//SEGON SELECT
$sqlSeconSel=oci_parse($conn, 'SELECT * FROM TIPO_ACTIVIDAD WHERE ID_ACTIVIDAD='.$idTActivitat.';');
oci_execute($sqlSeconSel);

$cadena .= "<table>";
$cadena .= "    <tr>";
$cadena .= "        <td>";
$cadena .= "            <select name='selTActi[]'>";
$cadena .= "                <option selected>Selecciona Tipus Activitat:</option>";
$cadena .= "                <option></option>";
while (($row=oci_fetch_array($sqlSeconSel,OCI_BOTH))!=false){
    $cadena.="              <option name='idSecondSel' id='".$row['ID']."'>".$row['NOM']."</option>";
}
$cadena .= "            </select>";
$cadena .= "        </td>";
$cadena .= "    </tr>";
$cadena .= "</table>";
$cadena .= "</form>";

echo $cadena;
echo "<div id='info'></div>";
?>

</body>
</html>

返回这些错误，但第一个选择有效，所以第二个没有，如果你在函数ajaxFuncio（selectobj）;将返回更改为警报，它会在该警报上返回没有问题的ID。所以错误行：

Notice: Undefined variable: idTActivitat in C:\xampp\htdocs\UF4\test_ajax.php on line 85

Warning: oci_execute(): in C:\xampp\htdocs\UF4\test_ajax.php on line 86

Warning: oci_fetch_array(): in C:\xampp\htdocs\UF4\test_ajax.php on line 94

我可以在浏览器上看到带有结果的图片：

I see that:

两个DropDownList与ajax和PHP

0 个答案: