Question

我有这个字符串：

First part of string. Second part one: Second part two; Third part: Fourth part 2014. Available online:

字符串是这样制作的：

字符串（点）的第一部分
第二部分（冒号）
第二部分二（分号）
第三部分（冒号）
第四部分
4位数字（点）
可在线获取（冒号）

如何使用正则表达式将此字符串拆分为数组？

谢谢。

Answer 1

您可能需要以下内容：

$array = preg_split('/\s*[:;.]\s*/', $str);

甚至：

$array = preg_split('/\s*[:;.]\s*/', $str, -1, PREG_SPLIT_NO_EMPTY);

Answer 2

$string = "First part of string. Second part one: Second part two; Third part: Fourth part 2014. Available online:";
preg_match("/(.+?)\.(.+?):(.+?);(.+?):(.+?)(\d{4})\.(.+?):/",$string,$m);
print_r($m);

输出：

Array
(
    [0] => First part of string. Second part one: Second part two; Third part: Fourth part 2014. Available online:
    [1] => First part of string
    [2] =>  Second part one
    [3] =>  Second part two
    [4] =>  Third part
    [5] =>  Fourth part 
    [6] => 2014
    [7] =>  Available online
)

希望它能帮到你。

Answer 3

使用：

([a-zA-Z ]+)\. ([a-zA-Z ]+): ([a-zA-Z ]+); ([a-zA-Z ]+): ([a-zA-Z ]+)([0-9]{4})\. ([a-zA-Z ]+):

结果：

First part of string
Second part one
Second part two
Third part
Fourth part 
2014
Available online

正则表达式和PHP - 如何匹配此字符串？

3 个答案: