我有一个页面,其中一个下拉列表为Report1和Report2。如果我选择Report1,它将填充startdate和enddate。我将选择startdate和end date然后cliick on view报告它将执行ajax调用并获取数据并显示在表中,我正在使用数据表。
我有第二个库存的默认排序,我也可以对其他列进行排序。如果我对其他列进行排序,然后选择其他报告Report2,然后选择startdate adn end date,然后点击查看报告按钮。再次如果我选择Report1和startdate和end date并点击查看报告按钮,它将对另一列进行排序,但不对默认排序列进行排序。任何帮助都会很明显。
以下是我的代码
$('#userTable').dataTable({
"bProcessing" : false,
"bServerSide" : false,
"bFilter" : false,
"bSearchable" : false,
"oLanguage" : {
"sZeroRecords" : "No Active Users Found",
"sInfo" : "Total Records Found: _TOTAL_ "
},
"aaSorting" : [ [ 2, "asc" ] ],
"aoColumnDefs" : [ {
"mData" : "emailAddr",
"sWidth" : "20%",
"aTargets" : [ 0 ]
}, {
"mData" : null,
"sWidth" : "20%",
"mRender" : function(data, type, row) {
return row.firstNm + ' ' + row.lastNm;
},
"bSortable" : false,
"aTargets" : [ 1 ]
}, {
"mData" : "retailerId",
"sWidth" : "20%",
"aTargets" : [ 2 ]
}, {
"mData" : "role",
"sWidth" : "20%",
"aTargets" : [ 3 ]
}, {
"mData" : "contactPhone",
"bSortable" : false,
"sWidth" : "20%",
"aTargets" : [ 4 ]
} ],
"fnInfoCallback": function( oSettings, iStart, iEnd, iMax, iTotal, sPre ) {
return 'Displaying '+iStart+' to '+iEnd+' of ' +iTotal + ' entries';
}
答案 0 :(得分:1)
请使用这种方式:
counts = dict()
for word in x: # x is file named "f2.txt"
words = word.split()
print words
counts[words] = counts.get(words,0) + 1
print counts
答案 1 :(得分:0)
如果我理解正确你想要一个会返回默认顺序的函数吗?如果是这种情况,我认为以下内容将有所帮助: