Question

在C中，我们可以使用键盘中的关键字char将输入作为字符

scanf("%c", &ch);

但是在Java中如何做到这一点？

我试过这个：

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
    System.out.println("Enter a character: ");
    char c = scanner.next().charAt(0);
    System.out.println("You have entered: "+c);
  }
}

Answer 1

您可以使用扫描仪从输入中读取：

Scanner scanner = new Scanner(System.in); 
char c = scanner.next().charAt(0); //charAt() method returns the character at the specified index in a string. The index of the first character is 0, the second character is 1, and so on.

Answer 2

您只需使用(char) System.in.read();投射到char即可将int转换为char

Answer 3

使用System类

char yourChar = System.in.read()

Answer 4

以下是示例程序。

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class ReadFromConsole {

  public static void main(String[] args) {

    System.out.println("Enter here : ");

    try{
        BufferedReader bufferRead = new BufferedReader(new InputStreamReader(System.in));

        String value = bufferRead.readLine();

        System.out.println(value);
    }
    catch(IOException e)
    {
        e.printStackTrace();
    }
  }
}

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Answer 5

使用java你可以这样做：

使用扫描仪：

Scanner reader = new Scanner(System.in);
String line = reader.nextLine();
// now you can use some converter to change the String value to the value you need.
// for example Long.parseLong(line) or Integer.parseInt(line) or other type cast

使用BufferedReader：

BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
String line = reader.readLine();
// now you can use some converter to change the String value to the value you need.
// for example Long.parseLong(line) or Integer.parseInt(line) or other type cast

在这两种情况下，您需要传递默认输入，在我的情况下是System.in

Answer 6

使用：

char ch=**scanner.nextChar**()

Answer 7

我遇到了同样的困难，而这就是我所使用的：

} public static void main(String[] args) {

Scanner scan = new Scanner(System.in);
System.out.print("Please enter the string: ");
String input = scan.next();
System.out.print("Please enter the required symbol: ");
String symbol = scan.next();        
char symbolChar = symbol.charAt(0);

这很好用。我们的想法是从字符串中获取其中唯一的字符。

Answer 8

qsort(dataset, total, sizeof(flow_data), num_compare);

Answer 9

import java.util.Scanner;

class CheckVowel {

    public static void main(String args[]) {   
        Scanner obj= new Scanner(System.in);

        char a=obj.next().charAt(0);

        switch(a) {    
            case 'a':  //cases can be used together for the same statement
            case 'e':
            case 'i':
            case 'o':
            case 'u':
            case 'A':
            case 'E':
            case 'I':     
            case 'O':
            case 'U':
                     {
                System.out.println("Vowel....");   
                break;
               }    
            default:    
                System.out.println("Consonants....");
        }
    }
}

Answer 10

import java.util.Scanner;
public class Main{
public static void main(String args[]){
   Scanner sc = new Scanner(System.in);
   System.out.println("Enter a character:");
String str = next();
char c = str.charAt(0);
System.out.println(c);
sc.close();
}
[Output of this program.][1]}

如何在java中输入字符

10 个答案: