Question

我想提取以下String：

http://media.zenfs.com/fr_FR/News/AFP/a418cb581c41fd9c36b0d24c054ad4c623bab222.jpg

来自String：

https://s1.yimg.com/bt/api/res/1.2/yqEp3ogcVvfSaDSSIq.Llg--/YXBwaWQ9eW5ld3M7Zmk9ZmlsbDtoPTg2O3E9NzU7dz0xMzA-/http://media.zenfs.com/fr_FR/News/AFP/a418cb581c41fd9c36b0d24c054ad4c623bab222.jpg

之前，提取，我想检查全局字符串是否包含多个时间＆＃34; http＆＃34;一定要在需要时提取jpg。

我该怎么做？

Answer 1

提取如下数据：

var myStr = "https://s1.yimg.com/bt/api/res/1.2/yqEp3ogcVvfSaDSSIq.Llg--/YXBwaWQ9eW5ld3M7Zmk9ZmlsbDtoPTg2O3E9NzU7dz0xMzA-/http://media.zenfs.com/fr_FR/News/AFP/a418cb581c41fd9c36b0d24c054ad4c623bab222.jpg"
var splittedStr = myStr.split("-");
var extractedStr = splittedStr[3].slice(1);

了解有多少＆＃34; http＆＃34;存在于字符串中：

var count = (myStr.match(/http/g)).length;

Answer 2

希望有所帮助

var source = "https://s1.yimg.com/bt/api/res/1.2/yqEp3ogcVvfSaDSSIq.Llg--/YXBwaWQ9eW5ld3M7Zmk9ZmlsbDtoPTg2O3E9NzU7dz0xMzA-/http://media.zenfs.com/fr_FR/News/AFP/a418cb581c41fd9c36b0d24c054ad4c623bab222.jpg"
var temp = source.replace("https","http").split("http");
var result = 'http'+temp[2];

Answer 3

使用split（）

var original = "https://s1.yimg.com/bt/api/res/1.2/yqEp3ogcVvfSaDSSIq.Llg--/YXBwaWQ9eW5ld3M7Zmk9ZmlsbDtoPTg2O3E9NzU7dz0xMzA-/http://media.zenfs.com/fr_FR/News/AFP/a418cb581c41fd9c36b0d24c054ad4c623bab222.jpg";
original = original.split('-/');
alert($(original)[original.length-1]);

您的需求网址显示在提醒对话框中

Answer 4

您可以使用正则表达式：

str.match(/(http?:\/\/.*\.(?:png|jpg))/i)

FIDDLE

从javascript String中提取url

4 个答案: