Question

我有一个谷歌表单，提交时调用“on form submit”函数，包括javascript .substring（start，finish）方法。奇怪的是，在我的测试代码中它工作正常但是当它实际上必须使用“提交时”代码实现时，我得到一个错误，说： TypeError：无法调用undefined的方法“substring”。（第26行，文件“代码”）

这是我的测试代码，它可以正常工作（调用Browser.msgBox）

function test()
{

  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheets()[0];  //assumes that sheet containing header columns is first sheet
  var lastRow = sheet.getLastRow();
  var lastColumn = sheet.getLastColumn();
  var values = SpreadsheetApp.getActiveSheet().getRange(1, 1, 1, lastColumn).getValues();

  //variables with form submit data would go here but not for this testing


  var dataDump = "\n\n"
  var headerValue = values[0][5];
  var headerValue5 = headerValue.substring(0,5);

  Browser.msgBox(headerValue5);
}

此代码生成错误...

function onFormSubmit(e) 
{

  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheets()[0];  //assumes that sheet containing header columns is first sheet
  var lastRow = sheet.getLastRow();
  var lastColumn = sheet.getLastColumn();
  var values = SpreadsheetApp.getActiveSheet().getRange(1, 1, 1, lastColumn).getValues();

  //define variables
  var timeStamp = e.values[0];
  var name = e.values[1];
  var email = e.values[2];
  var emailSubject = "QMG periodic wRVU responses for ";
  emailSubject = emailSubject + timeStamp;
  var dataDump = "\n\n";

  for (var i = 3; i <= e.values.length; i++)
  {
    var headerValue = values[0][i];
    var responseValue = e.values[i];
    var responseValue5 = responseValue.substring(0,5);  //error here !!!!!!
    i++;  //increment i to get detailsValue
    var detailsValue = e.values[i];
      dataDump = dataDump + headerValue;
      dataDump = dataDump + ":\n\n";
      dataDump = dataDump + responseValue;
      dataDump = dataDump + "\n";
      dataDump = dataDump + detailsValue;
      dataDump = dataDump + "\n\n*********************\n\n";

  }

  MailApp.sendEmail(email, emailSubject, dataDump);  
}

删除带注释的行“//错误在这里!!!!!!”工作正常，所以我知道它正在读取数组数据。计划是使用.substring（）来确定一些格式，以便让它工作。

提前致谢...

Answer 1

这里没有专业人士，但我认为我对这个问题有所预感。

var array = ["aaa", "bbb", "ccc"];

for (var i = 0; i <= array.length; i++) {
    console.log(array[i]);
}

查看运行上述代码时，我会在undefined，最后得到一个console.log 由于i <= array.length。

在.substring上运行undefined之类的字符串方法会引发错误。

将<=更改为<，您应该好好去。

谷歌应用程序脚本TypeError：无法调用方法＆＃34; substring＆＃34;未定义的

1 个答案: