Question

我有一个CSV file会解析并输入一个Array这是一个DYNAMIC ARRAY之后我会得到两个数组之间的区别但是我无法继续在我的计算中因为我的第二个数组无法获得该值。

这是我到目前为止所得到的

Option Explicit

Private Sub cmd_parse_Click()

Dim adata() As String
Dim time1() As String
Dim holder1, holder2
Dim time2() As String
Dim lngIndex As Integer
Dim totaltime() As String

Do Until ft1.AtEndOfStream
  On Error Resume Next
        a = ft1.ReadLine
        b = a
        p(0) = a
        r = r + 1
        Text1.Text = r
        z = Left(b, 1)
            adata = Split(a, ",")

If Not IsNumeric(z) Then
            For i = 0 To UBound(adata)
                Text3 = adata(i)
                    If Text3 <> "Time Stamp" Then
                        ft2.WriteLine Text3
                    End If
            Next

        Else

If holder1 = "" Then
            time1 = Split(a, ",")
            For lngIndex = 0 To UBound(time1)
                holder1 = time1(lngIndex)
            Next lngIndex

        Else
            time2 = Split(a, ",")
            For lngIndex = 0 To UBound(time2)
                holder2 = time2(lngIndex)
            Next lngIndex

        End If

    'subtract array time1 from time2

        If holder1 <> "" And holder2 <> "" Then
            For lngIndex = 0 To UBound(time2)
                holder3 = time2(lngIndex) - time1(lngIndex)

            Next lngIndex
        End If
  End If
DoEvents

Loop

请有人帮助我。

Answer 1

你还没有完全宣布数组time1和time2以及总时间......

通过使用empty（）声明它们，程序还不知道数组的大小......数组adata（）的大小是split（）函数，但其他数组不是

查看redim

您可能希望time1与adata的大小相同？：

ReDim time1(UBound(adata)) As String

将数组传递给VB6中的另一个数组

1 个答案: