Question

data = {'results' => [1, 1, 1, 1, 0, 0, 1, 1, 1, 0], 
        'weather' => ["bad", "bad", "bad", "good", "good", "good", "good", "good", "bad", "bad"]}

结果有十个条目，天气有十个条目，它们是对齐的并且彼此对应。如何从变量数据中删除两个来自天气的条目，以及相应的结果条目，其中天气==＆＃34;坏＆＃34; ？

Answer 1

如果我理解正确，你应该在weather数组中找到第一次出现'bad'，得到这个出现的索引并删除两个数组中的元素（并做两次）：

data = {'results' => [1, 1, 1, 1, 0, 0, 1, 1, 1, 0], 
        'weather' => ["bad", "bad", "bad", "good", "good", "good", "good", "good", "bad", "bad"]}

2.times do
  idx = data['weather'].index('bad')
  data['weather'].delete_at(idx)
  data['results'].delete_at(idx)
end

p data

结果：

{"results"=>[1, 1, 0, 0, 1, 1, 1, 0],
 "weather"=>["bad", "good", "good", "good", "good", "good", "bad", "bad"]}

Answer 2

以下作品：

index_array = []
counter = 0
data['weather'].each_with_index do |a,i|
  if a=="bad" and counter !=2
    data['results'][i] = nil
    data['weather'][i] = nil
    counter = counter + 1
  end
end

data['results'] = data['results'].compact
data['weather'] = data['weather'].compact

从Ruby的Ruby哈希中删除项目

2 个答案: