Question

发现此网站上的代码和此代码适用于我的情况，但有一种方法可以让我获得已用时间＆＃34;持续时间＆＃34;直接使用SimpleDateFormat格式化它（＆＃34; HH：mm：ss＆＃34;）？更具体一点..我想要这样的东西没有得到HH：mm：来自1970年的ss :) 例如：＆＃34; 00：00：10＆＃34;

SimpleDateFormat sdf = new SimpleDateFormat（＆＃34; HH：mm：ss＆＃34;）; duration = endTime-startTime; durationStr = sdf.format（持续时间）;

      public long startTime;
      public long endTime;
      String durationStr;
      public long durationSec;
      public long minutes,seconds,hours;

        @Override
            public void onCreate(){
            super.onCreate();
            //service started
            startTime = System.currentTimeMillis();
        }

                public getLastLocation(){
            //this is where the service ends
                endTime=System.currentTimeMillis();
                Date d = new Date(endTime);
                Date d1 = new Date(startTime);
                duration = d.getTime() - d1.getTime();
                durationSec = TimeUnit.MILLISECONDS.toSeconds(duration);
                seconds = durationSec % 60;
                durationSec/= 60;
                minutes = durationSec % 60;
                durationSec /= 60;
                hours = durationSec % 24;
                durationStr=String.valueOf(hours)+" "+String.valueOf(minutes)+" "+String.valueOf(seconds);

Answer 1

你可以试试这个：

注意：我在这个例子中没有使用任何服务，所以我使用了postDelayed，它在5秒后执行代码。基于此，我正在计算从活动开始到postDelayed

结束的持续时间

long delayedTime, currTime;
TextView text;
currTime = System.currentTimeMillis();
            new Handler().postDelayed(new Runnable() {

                    @Override
                    public void run() {
                        delayedTime = System.currentTimeMillis();
                        text.setText("" + getDurationString((int)((delayedTime - currTime) * 0.001)));
                    }
                }, 5000);

-

public String getDurationString(int seconds) {
    int hours = seconds / 3600;
    int minutes = (seconds % 3600) / 60;
    seconds = seconds % 60;
    return twoDigitString(hours) + " : " + twoDigitString(minutes) + " : " + twoDigitString(seconds);
                }

private String twoDigitString(int number) {
  if (number == 0) {
     return "00";
  }
  if (number / 10 == 0) {
     return "0" + number;
  }
  return String.valueOf(number);
}

[conversion]

如何将服务的持续时间格式化为＆＃34; HH：mm：ss＆＃34;

1 个答案: