Question

 #include <iostream>


using namespace std;

int main()
{   int a;
    int b;
    int sum;
    string ans = "";
    cout << "Input a directive. Upon it finishing it will terminate. Codes are: \n Calc \n Exit \n";
    cin >> ans;
    if(ans == "Calc")
    {
        cout << "Welcome to Calculator! Put in a number. Press Enter to put in number. \n";
        cin >> a;

        cout << "Next number \n";
        cin >> b;
        sum = a + b;

        cout << sum << " Is the amount! \n";
        cout << "Input a directive. Upon it finishing it will terminate. Codes are: \n Calc \n Exit \n";
        ans = "";    
    }

    if(ans != "Calc")
    {    
        cout << "Okay";    
    }
}

这样可行，但是如果我不输入Calc，它什么都不做，但打印出来，但是如果我不再输入Calc，它会关闭。如果我输入计算，我可以通过它，当它给出答案，它没关系，然后我按任意键，它关闭。我是这个论坛/网站的新手，不确定是否正确的地方。

Answer 1

好吧，如果你想让程序再次从用户那里获取输入，那么你应该写它以便它做到这一点：

#include <iostream>
using namespace std;
int main()
{   int a;
    int b;
    int sum;
    while(true) 
    {
         string ans = "";
         cout << "Input a directive. Upon it finishing it will terminate. Codes are: \n Calc \n Exit \n";
         cin >> ans;
         if(ans == "Calc")
         {
             cout << "Welcome to Calculator! Put in a number. Press Enter to put in number. \n";
             cin >> a;

             cout << "Next number \n";
             cin >> b;
              sum = a + b;

              cout << sum << " Is the amount! \n";
          }
          else if(ans == "Exit") 
          {
              cout << "Bye!\n";    
              return 0;
          }
          cout << "Okay\n";    
     }
}

它工作，直到我输入第二个输入然后它关闭

1 个答案: