Question

这是我的代码，它从xampp外部数据库中检索数据并将其存储到解析为json的数组

<?php


/*
* Following code will list all the products
*/

// array for JSON response
$response = array();

// include db connect class
require_once __DIR__ . '/conectaDB.php';

// connecting to db
$db = new DB_CONNECT();

// get all products from products table
$result = mysql_query("select cd.id, cd.dt_ini_camp, cd.dt_fim_camp, cd.descricao, + (select sum(quantidade) from lin_doc where id_cab_doc = cd.id) as qtd from cab_doc cd where cd.id_tipo_doc = 1") or die(mysql_error());


 // check for empty result
if (mysql_num_rows($result) > 0) {
// looping through all results
// products node



while ($row = mysql_fetch_array($result)) {

    // temp user array
    $product = array();
    $product["id"] = $row["id"];
    $product["dt_ini_camp"] = $row["dt_ini_camp"];
    $product["dt_fim_camp"] = $row["dt_fim_camp"];
    $product["descricao"] = $row["descricao"];
    $product["qtd"] = $row["qtd"];      



    // push single product into final response array
    $response["cab_doc"] = array();
    array_push($response["cab_doc"], $product);
}




// success
$response["success"] = 1;


// echoing JSON response
echo json_encode($response);
} else {
// no products found
$response["success"] = 0;
$response["message"] = "No products found";

// echo no users JSON
echo json_encode($response);
}
?>

输出：

{"cab_doc":[{"id":"69","dt_ini_camp":"2012-12-22","dt_fim_camp":"2012-12-  26","descricao":"cadqadadad","qtd":null}],"success":1}

我的问题是，这是最后一条记录，我想要所有，最新消息请帮助

Answer 1

尝试使用 while() 循环

这样的内容

while ($row = mysql_fetch_array($result)) {

    // temp user array
    $product = array(
        'id' => $row["id"],
        'dt_ini_camp' => $row["dt_ini_camp"],
        'dt_fim_camp' => $row["dt_fim_camp"],
        'descricao' => $row["descricao"],
        'qtd' => $row["qtd"]
    );

    // push single product into final response array

    array_push($response["cab_doc"], $product);
}

您可以尝试将其添加到 $response['cab_doc'] 数组中，如下所示：

$response['cab_doc'][] = $product;

这对你有什么影响？

编辑：试试这个：

$response["cab_doc"] = array();
while ($row = mysql_fetch_array($result)) {

    // temp user array
    $product = array(
        'id' => $row["id"],
        'dt_ini_camp' => $row["dt_ini_camp"],
        'dt_fim_camp' => $row["dt_fim_camp"],
        'descricao' => $row["descricao"],
        'qtd' => $row["qtd"]
    );

    // push single product into final response array

    array_push($response["cab_doc"], $product);
}

编辑＃2：

<?php


/*
* Following code will list all the products
*/

// array for JSON response
$response = array();

// include db connect class
require_once __DIR__ . '/conectaDB.php';

// connecting to db
$db = new DB_CONNECT();

// get all products from products table
$result = mysql_query("select cd.id, cd.dt_ini_camp, cd.dt_fim_camp, cd.descricao, + (select sum(quantidade) from lin_doc where id_cab_doc = cd.id) as qtd from cab_doc cd where cd.id_tipo_doc = 1") or die(mysql_error());


 // check for empty result
if (mysql_num_rows($result) > 0) {
// looping through all results
// products node



$response["cab_doc"] = array();
while ($row = mysql_fetch_array($result)) {

// temp user array
$product = array(
    'id' => $row["id"],
    'dt_ini_camp' => $row["dt_ini_camp"],
    'dt_fim_camp' => $row["dt_fim_camp"],
    'descricao' => $row["descricao"],
    'qtd' => $row["qtd"]
);

// push single product into final response array

array_push($response["cab_doc"], $product);
//or
// $response['cab_doc'][] = $product;
}




// success
$response["success"] = 1;


// echoing JSON response
echo json_encode($response);
} else {
// no products found
$response["success"] = 0;
$response["message"] = "No products found";

// echo no users JSON
echo json_encode($response);
}
?>

从数组php中获取所有数据

1 个答案: