Question

让我试着解释一下我在这里发生了什么。这是一个成员区域，单击一个按钮时，将调用此脚本。理想情况下，它会减去项目的成本（点数），并使用新的点变量更新数据库。

脚本：

<?php
session_start();
if ($_SESSION['email'])
{
    $dbemail=$_SESSION['email'];

//connecting here
    // Check connection
    if (mysqli_connect_errno())
    {
       echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }

    $result = mysqli_query($con,"SELECT * FROM tsfs_members WHERE email = '$dbemail'");
    $row = mysqli_fetch_array($result);

//putting rows into variables to make calling them easier
    $id = $row["id"];
    $firstname = $row["firstname"];
    $lastname = $row["lastname"];
    $email = $row["email"];
    $streetaddress = $row["streetaddress"];
    $city = $row["city"];
    $state = $row["state"];
    $zip = $row["zip"];
    $points = $row["points"];
    $date = $row["date"];

$newpoints = $points - '75';

$sql = "UPDATE tsfs_members SET points='50' WHERE id=?";

    $stmt = $mysqli->prepare($sql);
    $stmt->bind_param('s',$id);
    $stmt->execute();       

    echo "Thanks! Your have" . $newpoints . "left in your account";
   }
   else 
{
  echo "<div style='text-align:center; color:#ff0000; font-size:200%; margin-top:40px; font-weight:bold;'>You must be a registered user!</div>";
}

?>

这会在非对象

上抛出一个成员函数prepare（）的调用错误

任何帮助将不胜感激！

Answer 1

另一个question you asked包含：

mysqli_query($con,"UPDATE feedback SET approved=1 WHERE approved='0'");

对于这个也一样。

如：

$stmt = $con->prepare($sql);

而不是：

$stmt = $mysqli->prepare($sql);

因为您已经使用$con传递数据库连接：

$result = mysqli_query($con,"SELECT...

$mysqli未定义，这就是non-object错误的来源。

无法将数据库更新到UPDATE

1 个答案: