我在firebug中收到上述标题错误。不确定可能是什么问题..
我的观点
app.View.TrendsView = Backbone.View.extend({
template: _.template($('#trends-template').html()),
render: function() {
this.$el.empty();
this.$el.html(this.template({
trends: this.model.toJSON()
}));
return this.$el;
}
});
致电
app.views.trends = new app.View.TrendsView({ model : model });
萤火虫
我的模型创建
var m = new app.Model.TrendModel();
m.url='/trends'
m.set('login', login);
m.save(null, {
success: function(collection, model, response){
app.views.trends = new app.View.TrendsView({
model : model
});
$('#tab-content').empty();
$('#tab-content').append(app.views.trends.render());
},
error: function(collection, model, response){
}
});
m.destroy();
春季代码
@RequestMapping(value = "/trends", method = RequestMethod.POST, produces = "application/json")
@ResponseBody
public TrendResultDTO getTrends(@RequestBody UserDTO user,
HttpServletResponse response) {
答案 0 :(得分:1)
save
接受选项哈希中的success
和error
回调 将通过参数(model, response, options)
但回调所期望的参数为collection, model, response
,这意味着您将响应作为模型传递给视图,如控制台日志所示。
尝试
m.save(null, {
success: function(model, response, options){
app.views.trends = new app.View.TrendsView({
model : model
});
// ...
},
error: function(model, response, options){
}
});