我正在努力应对挑战并解密一些东西...... 但我无法弄清楚它是什么样的加密方式。
<script>
function decrypt(inp) {
result = "";
for (var i=0; i<inp.length; i++) {
result = result + String.fromCharCode(inp.charCodeAt(i) ^ "ENCRYPTED".charCodeAt(i % 9));
}
return result;
}
/*
* Use this function to verify the security code
*/
eval(decrypt("O8& 06-eye(6<:$=**ef-'4|t61&-&!*yt>Nencr06tm07;&ryvrel+;.rp\u0019$0- `3=.xfidugjrxmtudchcz7%9ebe\u0003\"&1~$*3m|orhy}eyxnsrvtm*0#cty\u001d51,k>,%qbxevlgcsdpdebcnk<,=tcd\b\/7:w ;2lwbcapytdye~ctp|+1(ner\u00141 -j5!4zk|tqmln~oy`tcbef-'4pre\t$:+|)?#mvinv{ppixdunetyx:0)ehc\u001f8$<k4*9k`upblmeo~riprcdm 6?yvt\b%1&m\"6'|wheyj{yqieteherq>!(dcn\u000e3-8z5+2fq~yh}lddscbyvrel+;.rp\u0019$0-`3=.xfid|gjrxmtudchcz7%9ebe\u0003\"&1~$*3m|orh`}lddscbyvrel+;.rp\u0019$0-`3=.xfidtj{ymieteherq>!(dcn\u000e3-8z5+2fq~yaflmes~riprcdm 6?yvt\b%1&m\"6'|whep{ppixdunetyx:0)ehc\u001f8$<k4*9k`upeqmln~oy`tcbef-'4pre\t$:+|)?#mvinrgpytxye~jr\"Z]L7 :\u0017;45;00m=61:5'6hesbiyoOM8n&>*5t>NLG\/=:1 ,++`175?5!lluI[$Z)OM"));
var enabled = true;
function handle() {
if (!enabled) {
return;
}
if ($("#code").val().length >= 4) {
verify(parseInt($("#code").val()), function() {
var code = $("#code").val();
$.post("/unlock.php",
{ code: code, step: 3 },
function(data) {
if (data == "OK") {
document.location = "/4";
} else {
$("#code").val('');
}
}
);
});
}
} Ĵ
这是源代码的一部分。 有谁能告诉我如何解密这个? 我确实找到了......但我不确定是否有必要。
/ * jquery.utils.js:各种简单的实用功能 - 2k12 CS * /
(function($){
$.extend({
postJSON: function(url, data, callback) { return $.post(url, data, callback, "json"); },
base64_decode: function(input) {
var keyStr = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" +
"abcdefghijklmnopqrstuvwxyz0123456789+/=";
var output = ""; var chr1, chr2, chr3;
var enc1, enc2, enc3, enc4; var i = 0;
input = input.replace(/[^A-Za-z0-9\+\/\=]/g, "");
while (i < input.length) {
enc1 = keyStr.indexOf(input.charAt(i++));
enc2 = keyStr.indexOf(input.charAt(i++));
enc3 = keyStr.indexOf(input.charAt(i++));
enc4 = keyStr.indexOf(input.charAt(i++));
chr1 = (enc1 << 2) | (enc2 >> 4);
chr2 = ((enc2 & 15) << 4) | (enc3 >> 2);
chr3 = ((enc3 & 3) << 6) | enc4;
output = output + String.fromCharCode(chr1);
if (enc3 != 64) output = output + String.fromCharCode(chr2);
if (enc4 != 64) output = output + String.fromCharCode(chr3);
}
return output;
},
format_time: function(value) {
var minutes = Math.floor(parseInt(value) / 60);
var seconds = parseInt(value) - minutes * 60;
if (minutes < 10) minutes = '0' + minutes;
if (seconds < 10) seconds = '0' + seconds;
return minutes + ':' + seconds;
},
// return value seperated with dashes every $groupsize characters
seperate: function(value, groupsize) {
var splitexp = new RegExp(".{1," + $.xn(groupsize) + "}", "g");
var trailexp = new RegExp("[^-]{" + $.xn(groupsize) + "}-$", "g");
var groups = value.replace(/-/g, "").match(splitexp);
if(!(groups)) return "";
var result = groups.join("-");
if(value.match(trailexp)) result += "-";
return result;
},
debug: function(message) {
if(typeof(console) == "undefined") return false;
return console.log("[portal] " + message);
},
xh: function(value) {
return value.replace(/&/g, '&').replace(/</g, '<')
.replace(/>/g, '>').replace(/"/g, '"').replace(/`/g, '`');
},
xn: function(value) { return Number(value); },
xw: function(value) { return value.replace(/[^a-zA-Z0-9_]/, '_'); },
xclass: function(value, allow_spaces) {
allow_spaces = allow_spaces || false;
if(allow_spaces) return value.replace(/[^ a-zA-Z0-9_-]/, '_');
return value.replace(/[^a-zA-Z0-9_-]/, '_');
},
xu: function(value) {
return encodeURIComponent(value).replace(/!/g, '%21')
.replace(/'/g, '%27').replace(/\(/g, '%28')
.replace(/\)/g, '%29').replace(/\*/g, '%2A').replace(/`/g, '%60');
} });
})(jQuery的);
我有人能告诉我如何解密这个会很棒!