Question

当组状态= 0,1,2时总和为0，当它显示为0时总和为0

我的桌子：

|policies|
  |id|  |client|  |policy_business_unit_id|  |cia_ensure_id|   |state|       
   1      MATT                  1                   1             0
   2      STEVE                 2                   1             0
   3      BILL                  3                   2             1
   4      LARRY                 4                   2             1
   5      MESSI                 1                   1             1  
   6      DROGBA                1                   1             1   

|policy_business_units|
   |id|   |name|  |comercial_area_id|
     1     LIFE         2 
     2     ROB          1
     3     SECURE       2
     4     ACCIDENT     1

|comercial_areas|
   |id|   |name|
    1      BANK
    2      HOSPITAL

|cia_ensures|
   |id|   |name|
    1      SPRINT
    2      APPLE

以下是信息：

http://sqlfiddle.com/#!2/935e78/4

我试图在每列中加上状态= 0,1,2：

  SELECT 
   IF( p.state =0, COUNT( p.state ) , 0 ) AS state_0, 
   IF( p.state =1, COUNT( p.state ) , 0 ) AS state_1,
   IF( p.state =2, COUNT( p.state ) , 0 ) AS state_2, 
   p.policy_business_unit_id AS UNITS, 
   p.cia_ensure_id AS CIAS

FROM policies p
WHERE  p.policy_business_unit_id IN ( 1 ) 
AND p.cia_ensure_id =1
GROUP BY p.state

结果如下：

  STATE_0   STATE_1       STATE_2     UNITS    CIAS
    1           0          0           1       1
    0           2          0           1       1

如何获得此结果？

  STATE_0   STATE_1       STATE_2     UNITS    CIAS
    1           2          0           1       1

请相信我会得到各种帮助。感谢。

Answer 1

替换此

  SELECT 
   IF( p.state =0, COUNT( p.state ) , 0 ) AS state_0, 
   IF( p.state =1, COUNT( p.state ) , 0 ) AS state_1,
   IF( p.state =2, COUNT( p.state ) , 0 ) AS state_2,

通过

 SELECT 
   sum(CASE WHEN p.state =0 THEN  1 ELSE 0 end) AS state_0, 
   sum(CASE WHEN p.state =1 THEN  1  ELSE 0  END) AS state_1,
   sum(CASE WHEN p.state =2 THEN  1  ELSE 0  END) AS state_2,

Answer 2

如果您需要将state = 0或1或2的所有值组合在一起，那么您的查询必须略有不同。试试这个。

SELECT 
    SUM(CASE WHEN p.state = 0 THEN 1 ELSE 0 END) AS state_0,
    SUM(CASE WHEN p.state = 1 THEN 1 ELSE 0 END) AS state_1,
    SUM(CASE WHEN p.state = 2 THEN 1 ELSE 0 END) AS state_2,
    p.policy_business_unit_id AS UNITS, 
    p.cia_ensure_id AS CIAS 
FROM policies p
WHERE  p.policy_business_unit_id IN ( 1 ) 
    AND p.cia_ensure_id =1
GROUP BY CASE WHEN p.state IN (0,1,2) THEN 1 ELSE 0 END

这是一个有效的SQL FIDDLE，展示了它是如何运作的。

Answer 3

您可能会考虑使用policy_business_unit_id和cia_ensure_id进行分组，因为您可能不仅要报告1和1，还要报告所有组合。

SELECT 
sum(case when p.state = 0 then 1 else 0 end) AS state_0, 
sum(case when p.state = 1 then 1 else 0 end) AS state_1,
sum(case when p.state = 2 then 1 else 0 end) AS state_2, 
p.policy_business_unit_id AS UNITS, 
p.cia_ensure_id AS CIAS
FROM policies p
--WHERE  p.policy_business_unit_id IN ( 1 ) 
--AND p.cia_ensure_id =1
group by p.policy_business_unit_id, p.cia_ensure_id

如何总结群体价值？

3 个答案: