尝试使用Zend DB Table创建一个'join'语句 - zend framework 2

时间:2014-04-02 15:12:12

标签: php mysql zend-framework zend-framework2

我有一个模型需要在2个表上执行连接查询...让我们称之为friend_list和user_profile。

我有一段时间试图将zend样式代码放在一起以产生我需要完成此操作的正确查询...下面是所需的查询:

SELECT friend_list.friend_id, user_profile.id, user_profile.username
FROM `friend_list`
INNER JOIN `user_profile`
ON friend_list.friend_id = user_profile.id
where user_id = 1

这是我的model_friends

<?php
//model created to add user to database, sendmail etc...
require_once 'Zend/Db/Table/Abstract.php';

class Model_Friends extends Zend_Db_Table_Abstract
{
protected $_name = "friend_list";

public function fetchFriendList($userID)
{

    $accountsTable = array('up' => 'user_profile');
    $select = $this->select()
                   ->from($this->_name)
                   ->join($accountsTable, 'up.id = friend_List.friend_id', array())
                   ->where("up.id = ?", $userID);

    $result = $this->fetchAll($select);


    if ($result !== null){
        echo $select;
        return $result;
    } else {
        echo "no records found";
    }   
  }
}

上面的模型产生了以下SQL语句,这不是我想要的......

SELECT `friend_list`.* 
FROM `friend_list` 
INNER JOIN `user_profile` 
AS `up` 
ON up.id =     friend_List.friend_id 
WHERE (up.id = '1') 

按要求添加表格结构:

DROP TABLE IF EXISTS `buzz`.`friend_list`;
CREATE TABLE  `buzz`.`friend_list` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(11) NOT NULL,
`friend_id` int(11) NOT NULL,
`approved_timestamp` date NOT NULL,
`status` varchar(15) DEFAULT 'pending',
PRIMARY KEY (`id`) USING BTREE
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;

DROP TABLE IF EXISTS `buzz`.`user_profile`;
CREATE TABLE  `buzz`.`user_profile` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`mob` varchar(50) NOT NULL DEFAULT 'no info',
`dob` varchar(50) NOT NULL DEFAULT '',
`yob` varchar(50) NOT NULL DEFAULT '',
`language` varchar(75) NOT NULL DEFAULT 'English',
`gender` varchar(25) NOT NULL DEFAULT 'no info',
`about` varchar(1000) NOT NULL DEFAULT 'no info',
`country` varchar(45) NOT NULL DEFAULT 'no info',
`username` varchar(45) NOT NULL,
PRIMARY KEY (`id`,`username`) USING BTREE
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;

3 个答案:

答案 0 :(得分:1)

尝试将Zend_Db_Select对象更改为以下内容:

$select = $this->select()
    ->join($accountsTable, 'friend_list.friend_id = user_profile.id', array())
    ->where('user_profile.id = ?', $userID)
    ->reset('columns')
    ->columns(array('friend_list.friend_id', 'user_profile.id', 'user_profile.username'));

答案 1 :(得分:1)

这不是问题的答案,但由于我无法发表评论,我将在此发布。我发现以下网站对加入示例很有帮助。

github.com

答案 2 :(得分:0)

我的model_friends脚本的最终结果如下:

<?php
//model created to add user to database, sendmail etc...
require_once 'Zend/Db/Table/Abstract.php';

class Model_Friends extends Zend_Db_Table_Abstract
{
protected $_name = "friend_list";

public function fetchFriendList($userID)
{       
    $select = $this->select()
                   ->from($this)
                   ->setIntegrityCheck(false)
                   ->join(array('u'=>'user_profile'), 'friend_list.friend_id =u.id', array())
                   ->columns(array('u.id', 'u.username'))
                   ->where("friend_list.user_id = ?", $userID);     

    $result = $this->fetchAll($select);                    
    if ($result !== null){
        echo $select;
        return $result;
    } else {
        echo "no records found";
    }   
  }
}