Question

建议我有以下代码：

#include <boost/asio/io_service.hpp>
#include <boost/thread.hpp>

#include <condition_variable>
#include <iostream>
#include <mutex>

const int THREAD_POOL_SIZE = 2;

std::condition_variable g_cv;
std::mutex g_cv_mutex;
bool g_answer_ready;

void foo()
{
  std::cout << "foo \n";
  std::unique_lock<std::mutex> lock(g_cv_mutex);
  g_answer_ready = true;
  g_cv.notify_all();
}

int main()
{
  boost::asio::io_service io_service;

  for (int i = 0; i < 10; ++i)
  {
    std::auto_ptr<boost::asio::io_service::work> work(new boost::asio::io_service::work(io_service));

    boost::thread_group threads;
    for (int i = 0; i < THREAD_POOL_SIZE; ++i)
    {
      threads.create_thread(boost::bind(&boost::asio::io_service::run, &io_service));
    }

    std::unique_lock<std::mutex> lock(g_cv_mutex);

    io_service.post(foo);

    g_answer_ready = false;
    g_cv.wait_for(lock, std::chrono::milliseconds(2000));

    if (!g_answer_ready)
    {
      std::cout << "timed_out \n";
    }

    io_service.stop();
    threads.join_all();
  }
}

节目发布之间的输出会有所不同。例如，

foo
timed_out
foo
foo

但是，如果我在循环中移动boost :: asio :: io_service对象构造，它会按预期工作：

foo
foo
foo
foo
foo
foo
foo
foo
foo
foo

为什么呢？我究竟做错了什么？我该如何解决？

提升1.54，MSVC-11.0

Answer 1

如果我理解正确，您需要修复循环中的最后一行（请参阅说明的注释）：

// io_service.stop();
// threads.join_all();

work.reset(); // <- signal to process all pending jobs and quit from io_service::run function
threads.join_all(); // <- wait for all threads
io_service.reset(); // <- now `io_service` can accept new tasks

因此，原始代码中存在两个问题：

io_service.stop()将取消已发布但尚未处理的作业（通常这不是程序员想要的），
io_service.reset()需要将io_service的状态从“已停止”更改为“准备接受新工作”。

提升asio和条件变量 - 奇怪的输出

1 个答案: