Question

我正在尝试使用以下代码获取页面内容（android）：

DefaultHttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
httpGet.setHeader("User-Agent", "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_3) AppleWebKit/536.28.10 (KHTML, like Gecko) Version/6.0.3 Safari/536.28.10");
try {
  HttpResponse execute = client.execute(httpGet);
  InputStream content = execute.getEntity().getContent();

  BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
  String s = "";
  while ((s = buffer.readLine()) != null) {
    builder.append(s);
  }

} catch (Exception e) {
  e.printStackTrace();
}

这适用于Google等网站，但我想访问的特定网站（http://www.swimrankings.net/index.php?internalRequest=athleteLookup&athlete_lastname=jansen&athlete_clubId=273&athlete_gender=-1）会返回PHP错误（Fatal error: Access to undeclared static property: Config::$defaultLanguage in C:\Data\htdocs\www.swimrankings.net\classes\BSLanguage.php on line 16）。

使用浏览器查看网站时，我不会收到此错误消息。我能做些什么来解决这个问题吗？

谢谢！

注意我已经尝试过使用内置的java URLConnection。我也尝试将标题设置为与safari显示我用于访问页面完全相同，但无济于事。

Answer 1

感谢@mthmulders的修复！问题是未定义 Accept-Language ，导致PHP出错。将其设置为语言（＆＃34; en＆＃34;，＆＃34; de＆＃34;，＆＃34; fr＆＃34;）解决了问题。

固定代码：

DefaultHttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
httpGet.setHeader("User-Agent", "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_3) AppleWebKit/536.28.10 (KHTML, like Gecko) Version/6.0.3 Safari/536.28.10");
httpGet.setHeader("Accept-Language", "en");
try {
  HttpResponse execute = client.execute(httpGet);
  InputStream content = execute.getEntity().getContent();

  BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
  String s = "";
  while ((s = buffer.readLine()) != null) {
    builder.append(s);
  }

} catch (Exception e) {
  e.printStackTrace();
}

Java返回的内容与我的浏览器显示的不同

1 个答案: