在我的通知中,我想在点击待处理意图时启动当前活动。在谷歌,发现了很多方法,我尝试了很多次,它没有工作。这是我的代码,
public void onStart(Intent intent, int startId)
{
super.onStart(intent, startId);
String startTime = intent.getStringExtra("Strar_time");
NotificationManager nm = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
long when = System.currentTimeMillis(); // notification time
Notification notification = new Notification(R.drawable.ic_launcher, "reminder", when);
notification.defaults |= Notification.DEFAULT_SOUND;
notification.flags |= notification.FLAG_AUTO_CANCEL;
notification.vibrate = new long[]{100, 200, 100, 500};
notification.defaults = Notification.DEFAULT_ALL;
Intent notificationIntent = new Intent(this, Goo.class);
notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP/* | Intent.FLAG_ACTIVITY_SINGLE_TOP*/);
PendingIntent contentIntent = PendingIntent.getActivity(getApplicationContext(), 0, notificationIntent , 0);
notification.setLatestEventInfo(getApplicationContext(), "It's about time", "Your time is "+startTime, contentIntent);
notification.contentIntent=contentIntent;
nm.notify(NOTIF_ID, notification);
NOTIF_ID++;
Log.i("NotiID",NOTIF_ID+"");
}
答案 0 :(得分:0)
尝试下面给出的这个功能,
private static void generateNotification(Context context, String message) {
int icon = R.drawable.launch_icon;
long when = System.currentTimeMillis();
NotificationManager notificationManager = (NotificationManager) context
.getSystemService(Context.NOTIFICATION_SERVICE);
Notification notification = new Notification(icon, message, when);
String title = context.getString(R.string.app_name);
Intent notificationIntent = null;
notificationIntent = new Intent(context, Main.class);
// set intent so it does not start a new activity
notificationIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
PendingIntent intent = PendingIntent.getActivity(context, 0,
notificationIntent, Intent.FLAG_ACTIVITY_NEW_TASK);
notification.setLatestEventInfo(context, title, message, intent);
notification.flags |= Notification.FLAG_AUTO_CANCEL;
// Play default notification sound
notification.defaults |= Notification.DEFAULT_SOUND;
// Vibrate if vibrate is enabled
notification.defaults |= Notification.DEFAULT_VIBRATE;
notificationManager.notify(0, notification);
}
答案 1 :(得分:0)
到目前为止,我发现只有一种工作方式是进行虚拟活动,启动它并在onRusume()中完成它。但是,这种技术只会将应用程序带到前面,并且在关闭时不会启动应用程序。 然后我使用以下解决方法将应用程序放在前面,如果它在后台运行,否则启动它。
<强>清单:强>
<application>
.
.
.
<activity
android:name=".DummyActivity"
/>
.
.
</application>
代码:
public class DummyActivity{
public static boolean isAppAlive;
@Override
protected void onResume() {
// start application if it is not alive
if(!isAppAlive){
PackageManager pmi = getPackageManager();
Intent intent = pmi.getLaunchIntentForPackage(Your applications package name);
if (intent != null){
startActivity(intent);
}
}
finish();
}
在您的主要活动的onCreateMethod。
@Override
public void onCreate(Bundle savedInstanceState) {
DummyActivity.isAppAlive = true;
}
很明显,当您的应用程序完全关闭时,isAppAlive将恢复为默认值false。因此,申请将开始。