Mongoose Mongodb查询一系列对象

时间:2014-04-02 08:58:58

标签: node.js mongodb mongoose

我正在努力获得使用Mongoose查询数组时我期望看到的内容。用户可以拥有与他/她的帐户相关联的许多房间。房间对象存储在集合中附加到用户的阵列中。只有一个名为users的集合。

考虑用户和房间的以下两种模式:

USER SCHEMA

var userSchema = mongoose.Schema({

local            : {
    username     : String,
    email        : String,
    password     : String,
    rooms        : {type:Array, default: []}
}  


});

ROOM SCHEMA

var roomSchema = mongoose.Schema({

     name: String

});

这是我试过的查询:

var User = require('../models/user');

User.find({ 'rooms.name' : req.body.username  }, 
            { rooms: 
                { $elemMatch : 
                   { 
                     name: req.body.username 
                   } 
                } 
            }, function (err, user) {

        if (err){
            return done(err);
        }    

        console.log("user:::", user);

        if (user) {
            console.log("ROOM NAME FOUND");
            req.roomNameAlreadyInUse = true;
            next();

        } else {
            req.roomNameAlreadyInUse = false;
            console.log("ROOM NAME NOT FOUND");
            next();

        }

    });

问题是这个查询似乎总是返回一个空数组,即使它应该包含某些东西,或者它应该什么都不返回。那么我如何搜索所有用户房间阵列以查看房间名称是否已经存在?

我还尝试了以下查询,但都没有成功:

User.find({local: {rooms: {$elemMatch: {name: req.body.username}}}}, function (err,     user) {

}



User.find({'local.rooms': {$elemMatch: {name: req.body.username}}}, function (err, user) {

}

我还应该指出数据库已填充,因为我可以在robomongo中看到数组(在创建用户帐户时创建了1个元素)。

正在填充从控制台输出到show database的示例数据(包括user.rooms数组):

  

db.users.find()   {" _id" :ObjectId(" 533c4db2b2c311a81be8a256")," local" :{"密码" :" $ 2a $ 08 $ 0yQQJ2y0726kZtkWY5mAPOgZhacOmZn0Fd8DlausiuMB   XE4ZblTXS","用户名" :"保罗","电子邮件" :" test"," rooms" :[{" name" :" paul"," id" :ObjectId(" 533c4db2b2c311a81be8a2   57")}],"状态" :"活跃" }," _v" :0}   {" _id" :ObjectId(" 533c4ddab2c311a81be8a258")," local" :{"密码" :" $ 2a $ 08 $ dC3CbDTkG5ozECDTu / IicO3Az0WdkzlGh2xDcb8j1CF /   FQhe5guZq","用户名" :" john"," email" :" test2"," rooms" :[{" name" :" john"," id" :ObjectId(" 533c4ddab2c311a81be8a   259")}],"状态" :"活跃" }," _v" :0}

2 个答案:

答案 0 :(得分:21)

我将其更改为使用findOne而不是find,现在可以使用了。我不太清楚为什么这应该有所作为。这是我使用的findOne函数:

User.findOne({'local.rooms': {$elemMatch: {name: req.body.username}}}, function (err, user) {

        if (err){
            return done(err);
        }    

        if (user) {
            console.log("ROOM NAME FOUND");
            req.roomNameAlreadyInUse = true;
            next();

        } else {
            req.roomNameAlreadyInUse = false;
            console.log("ROOM NAME NOT FOUND");
            next();

        }

    });

答案 1 :(得分:2)

findOne返回单个文档,其中find返回光标。一旦找到find的光标,您就结束了,没有其他文档了。

User.findOne({'local.rooms': {$elemMatch: {name: req.body.username}}}, (err,UserInfo) => {

        if (err){
            return res.status(400).json({Error:"Something went wrong please try again"})
        }    

        if (UserInfo) {
            console.log("ROOM NAME FOUND");
            req.roomNameAlreadyInUse = true;
            res.json({msg:"Room name found.",userData:UserInfo})

        } else {
            req.roomNameAlreadyInUse = false;
            console.log("ROOM NAME NOT FOUND");
            res.json({msg:"Room name not found."})
        }

    });