Question

我有三张桌子：

gallery_items
gallery_album_items
gallery_tags

我设法加入前两个表但是如何将gallery_tags表添加到以下查询中？：

SELECT *
FROM gallery_items
RIGHT JOIN gallery_album_items 
ON gallery_items.id=gallery_album_items.id 
WHERE gallery_items.name LIKE '%{$term}%' 
OR gallery_items.description LIKE '%{$term}%'

基本上我要添加的内容：

OR gallery_tags.tag LIKE '%{$term}%'

表格结构

gallery_items
id   name     description
12   Sharon   This is sharon's description
26   Rhett    This is rhett's description
33   Lincoln  This is lincoln's description


gallery_album_items
id   album
12   14 
26   12
33   7


gallery_tags
id   item     tag
23   12       blonde
43   26       tall
3    33       glasses

基本上我想要搜索＆＃34;金发＆＃34;的结果： Sharon 金发，位于相册中。

（你不必提供一个echo语句。这只是向你展示结果的一个例子。）

编辑 - 最终答案

SELECT DISTINCT gallery_items.id 
FROM gallery_items
RIGHT OUTER JOIN gallery_album_items ON gallery_items.id = gallery_album_items.id
LEFT JOIN gallery_tags ON gallery_items.id = gallery_tags.item
WHERE gallery_items.active !=  '0'
AND (gallery_items.name LIKE '%blonde%'
OR gallery_items.description LIKE '%blonde%'
OR gallery_tags.tag LIKE '%blonde%'

Answer 1

SELECT *

FROM gallery_items 

RIGHT OUTER JOIN gallery_album_items 

ON gallery_items.id=gallery_album_items.id 

LEFT OUTER JOIN  gallery_tags 

ON gallery_tags.id   =  gallery_album_items.id     

WHERE gallery_items.name LIKE '%{$term}%' 

OR gallery_items.description LIKE '%{$term}%'

OR gallery_tags.tag LIKE '%{$term}%'

Answer 2

关于这个

SELECT *
FROM gallery_items
RIGHT JOIN gallery_album_items 
   ON gallery_items.id=gallery_album_items.id 
LEFT JOIN gallery_tags
   ON gallery_tags.id = gallery_items.id
WHERE gallery_items.name LIKE '%{$term}%' 
OR gallery_items.description LIKE '%{$term}%'

Answer 3

SELECT *
FROM gallery_items
RIGHT JOIN gallery_album_items 
ON gallery_items.id=gallery_album_items.id
LEFT JOIN gallery_tags on gallery_items.id on gallery_tags.id  
WHERE gallery_items.name LIKE '%{$term}%' 
OR gallery_items.description LIKE '%{$term}%'

Answer 4

请尝试这个

select gi.name, gai.ablum, gt.tag 
    from 
    gallery_items as gi JOIN gallery_album_items as gai 
    on gt.id=gai.id 
    Join gallery_tags as gt 
    on gi.id=gt.items

Answer 5

您可以使用别名来编写连接查询，以便在考虑逻辑时更好地理解，而不是使用表名。我尝试了一个，希望它会有所帮助。

创建表格g_i（ id int， name varchar（20）， descp nvarchar（max））

插入g_i值（12，＆＃39; asf 12＆＃39;，＆＃39;说明12＆＃39;）插入g_i值（26，＆＃39; asf 26＆＃39;，＆＃39;描述26＆＃39;）插入g_i值（33，＆＃39; asf 33＆＃39;，＆＃39;描述33＆＃39;）从g_i

中选择*

创建表格g_a（ id int，专辑varchar（20））插入g_a值（12，＆＃39;专辑12＆＃39;）插入g_a值（26，＆＃39;专辑26＆＃39;）插入g_a值（33，＆＃39;专辑33＆＃39;）从g_a

中选择*

create table g_t（ id int， item int，标签nvarchar（40））插入g_t值（23,12，＆＃39;标记12＆＃39;）插入g_t值（43,46，＆＃39;标记26＆＃39;）插入g_t值（3,33，＆＃39;标记33＆＃39;）从g_t

中选择*

SELECT *

FROM g_i as i RIGHT JOIN g_a as ON i.id = a.id. LEFT JOIN g_t as t on t.item = i.id

在哪里i.name LIKE＆＃39;％t％＆＃39;或者i.descp LIKE＆＃39;％t％＆＃39;

如何从MySQL中的三个表中获取数据？

5 个答案: