Question

我有桌子。

SALESMAN_REGION
(
       SALESMAN_ID    INTEGER,
       REGION_ID      INTEGER
);

SALESMAN
(
       SALESMAN_ID    INTEGER,
       SALESMAN_NAME  VARCHAR2(50)       
);

TABLE SALES
(
       SALE_ID        INTEGER,
       PRODUCT_ID     INTEGER,
       SALESMAN_ID    INTEGER,
       YEAR           INTEGER,
       Quantity       INTEGER,
       PRICE          INTEGER
);

我需要这些信息托尼的销售额比凯文多。我写了这个查询

 select s.region_id,sum(s.quantity),s.salesman_id from   sales s where s.salesman_id in (
select sr.salesman_id from salesman_region sr
inner join
salesman sm on sm.salesman_id = sr.salesman_id
where 
sm.salesman_name = 'Tony' or sm.salesman_name = 'Kevin') group by s.region_id ,s.salesman_id order by s.region_id;

输出是：

REGION_ID   SUM(S.QUANTITY) SALESMAN_ID
1   10          1776             10
2   10          1603             30
3   20          1813             10
4   20          1479             30
5   30          1218             10
6   30          1516             30

但我不知道如何比较这种或其他方式。谁能帮我？

Answer 1

我会使用条件聚合来解决这个问题：

select s.region_id,
       sum(case when sm.salesman_name = 'Tony' then s.quantity else 0 end) as QTony,
       sum(case when sm.salesman_name = 'Kevin' then s.quantity else 0 end) as QKevin
from salesman_region sr inner join
     salesman sm
     on sm.salesman_id = sr.salesman_id inner join
     sales s
     on s.sales_man_id = sm.salesman_id
group by s.region_id
having (sum(case when sm.salesman_name = 'Tony' then s.quantity else 0 end) >
        sum(case when sm.salesman_name = 'Kevin' then s.quantity else 0 end) 
       )

注意：为此，它假定销售人员只在一个地区。如果不是这样，那么您的数据结构无法回答您的问题，因为您不知道哪些销售位于哪些区域。

Oracle如何比较行？

1 个答案: