Question

在视图部分，我想检查$ check值是否== true然后打开CJuiDialog

<?php
if($check==true)
{
    js:function(){$('#dialogDisplay').dialog('open');}
}
$this->beginWidget('zii.widgets.jui.CJuiDialog', array(// the dialog
    'id' => 'dialogDisplay',
    'options' => array(
        'title' => 'Display Setting',
        'autoOpen' => false,
        'modal' => true,
        'width' => 300,
        'height' => 200,
        'buttons' => array(
            array('text' => 'Submit', 'click' => 'js:function(){ document.myform.submit();}'),
            array('text' => 'Cancel', 'click' => 'js:function(){$(this).dialog("close");}')),
    ),
));
?>
<div class="divForForm">
    <form name="myform" action="/dataset/resetPageSize" method="post">  
        Items per page:
        <select name="filePageSize" class="selectPageSize">
            <option value="5">5</option>
            <option value="10" selected>10</option>
            <option value="20">20</option>
            <option value="50">50</option>
            <option value="100">100</option>
            <option value="200">200</option>                 
        </select>
        <br>
        Size: <input type="checkbox" name="size" checked />
        <input type="hidden" name="url" value="<? echo Yii::app()->request->requestUri; ?>" />

    </form>

</div>    

<?php $this->endWidget(); ?>

但它不起作用，我只是开始学习javascript，我不知道如何在$ check == true时运行它

Answer 1

您需要将脚本标记打印到客户端：

<?php
// If PHP variable $check is true
if($check == true) {
    // Print out jQuery ready function to the client side, 
    //   which will run when the page loads
    echo "<script>$(function(){ $('#dialogDisplay').dialog('open'); })</script>";
}

如果PHP变量为true，则Yii查看打开CJuiDialog

1 个答案: