我正在研究像素的平均值,我知道这个循环可以用于任何2d数组。但是如果src是Mat图像(OpenCV),它怎么能工作呢? 我在Mat函数的函数中传递这些参数有很多困难 我的问题有意义吗?
#include <iostream>
const unsigned dim = 3;
typedef int array_type [dim][dim];
这是循环:
void average(array_type& dest, const array_type& src)
{
// corners:
dest[ 0 ][ 0 ] =
(src[ 0 ][ 0 ] + src[ 0 ][ 1 ] + src[ 1 ][ 0 ] + src[ 1 ][ 1 ])/4;
dest[dim-1][ 0 ] =
(src[dim-1][ 0 ] + src[dim-2][ 0 ] + src[dim-1][ 1 ] + src[dim-2][ 1 ])/4;
dest[ 0 ][dim-1] =
(src[ 0 ][dim-1] + src[ 1 ][dim-1] + src[ 0 ][dim-2] + src[ 1 ][dim-2])/4;
dest[dim-1][dim-1] =
(src[dim-1][dim-1] + src[dim-2][dim-1] + src[dim-1][dim-2] + src[dim-2][dim-2])/4;
// top, bottom, and sides:
for (unsigned i = 1; i < dim - 1; ++i)
{
const unsigned j = dim - 1;
dest[0][i] =
(src[0][i-1] + src[0][i] + src[0][i+1] + src[ 1 ][i-1] + src[ 1 ][i] + src[ 1 ][i+1])/6;
dest[j][i] =
(src[j][i-1] + src[j][i] + src[j][i+1] + src[j-1][i-1] + src[j-1][i] + src[j-1][i+1])/6;
dest[i][0] =
(src[i-1][0] + src[i][0] + src[i+1][0] + src[i-1][ 1 ] + src[i][ 1 ] + src[i+1][ 1 ])/6;
dest[i][j] =
(src[i-1][j] + src[i][j] + src[i+1][j] + src[i-1][j-1] + src[i][j-1] + src[i+1][j-1])/6;
}
// middle:
for (unsigned i = 1; i < dim - 1; ++i)
{
for (unsigned j = 1; j < dim - 1; ++j)
{
dest[i][j] = (src[i-1][j-1] + src[i-1][j] + src[i-1][j+1] +
src[ i ][j-1] + src[ i ][j] + src[ i ][j+1] +
src[i+1][j-1] + src[i+1][j] + src[i+1][j+1]) / 9 ;
}
}
}
答案 0 :(得分:1)
我认为你只是想知道如何像在2D数组中那样访问Mat image
像素。请参阅以下代码:
for(int i=0; i<image.rows; i++)
{
for(int j=0; j<image.cols; j++)
{
value_from_Mat_array = image.at<uchar>(i,j);
}
}
因此,i,j
是与2D数组相似的索引。
答案 1 :(得分:1)
你可能根本不会使用opencv进行循环,而是使用filter2D()代替:
Mat img; // your original image
Mat res; // filtered
Mat kernel(3,3,CV_32F,Scalar(1.0f/9));
filter2D(img,res,-1,kernel);