嗨我需要在24小时的时间范围内实现一个滑块。我喜欢使用jquery ui slider。我写了下面的代码
<script type="text/javascript">
$(function() {
$(".slider-range").slider({
range: true,
min: 0,
max: 23.59,
step: 0.15
});
});
</script>
我喜欢的范围就像01:00 ---- 01:59
我如何给结肠(:)而不是点(。) 。另外,范围等于超过59,如05:85。请帮我创建一个时间滑块
答案 0 :(得分:48)
不要将小时作为一个单位,而是使用分钟。然后应用slide
事件将分钟转换为小时:
$(function() {
$(".slider-range").slider({
range: true,
min: 0,
max: 1440,
step: 15,
slide: function(e, ui) {
var hours = Math.floor(ui.value / 60);
var minutes = ui.value - (hours * 60);
if(hours.toString().length == 1) hours = '0' + hours;
if(minutes.toString().length == 1) minutes = '0' + minutes;
$('#something').html(hours+':'+minutes);
}
});
});
答案 1 :(得分:19)
改善Tatu的答案,获得“平民时间”的时间范围,12小时制和AM和PM指定。这是JSFIDDLE
*更新 - 我稍微更改了代码,以便最小值显示为“12:00 AM”,最大值显示为“11:59 PM”。小提琴也更新......
$( "#slider-range" ).slider({
range: true,
min: 0,
max: 1440,
step: 15,
values: [ 600, 720 ], //or whatever default time you want
slide: function(e, ui) {
var hours1 = Math.floor(ui.values[0] / 60);
var minutes1 = ui.values[0] - (hours1 * 60);
if(hours1.length == 1) hours1 = '0' + hours1;
if(minutes1.length == 1) minutes1 = '0' + minutes1;
if(minutes1 == 0) minutes1 = '00';
if(hours1 >= 12){
if (hours1 == 12){
hours1 = hours1;
minutes1 = minutes1 + " PM";
}
else{
hours1 = hours1 - 12;
minutes1 = minutes1 + " PM";
}
}
else{
hours1 = hours1;
minutes1 = minutes1 + " AM";
}
if (hours1 == 0){
hours1 = 12;
minutes1 = minutes1;
}
$('.slider-time').html(hours1+':'+minutes1);
var hours2 = Math.floor(ui.values[1] / 60);
var minutes2 = ui.values[1] - (hours2 * 60);
if(hours2.length == 1) hours2 = '0' + hours2;
if(minutes2.length == 1) minutes2 = '0' + minutes2;
if(minutes2 == 0) minutes2 = '00';
if(hours2 >= 12){
if (hours2 == 12){
hours2 = hours2;
minutes2 = minutes2 + " PM";
}
else if (hours2 == 24){
hours2 = 11;
minutes2 = "59 PM";
}
else{
hours2 = hours2 - 12;
minutes2 = minutes2 + " PM";
}
}
else{
hours2 = hours2;
minutes2 = minutes2 + " AM";
}
$('.slider-time2').html(hours2+':'+minutes2);
}
});
答案 2 :(得分:9)
这是我的24小时版本,基于输入字段的两个答案
的Javascript
jQuery(function() {
jQuery('#slider-time').slider({
range: true,
min: 0,
max: 1440,
step: 15,
values: [ 600, 1200 ],
slide: function( event, ui ) {
var hours1 = Math.floor(ui.values[0] / 60);
var minutes1 = ui.values[0] - (hours1 * 60);
if(hours1.length < 10) hours1= '0' + hours;
if(minutes1.length < 10) minutes1 = '0' + minutes;
if(minutes1 == 0) minutes1 = '00';
var hours2 = Math.floor(ui.values[1] / 60);
var minutes2 = ui.values[1] - (hours2 * 60);
if(hours2.length < 10) hours2= '0' + hours;
if(minutes2.length < 10) minutes2 = '0' + minutes;
if(minutes2 == 0) minutes2 = '00';
jQuery('#amount-time').val(hours1+':'+minutes1+' - '+hours2+':'+minutes2 );
}
});
});
HTML
<label for="amount-time">Time</label>
<input type="text" name="amount-time" id="amount-time" style="border: 0; color: #666666; font-weight: bold;" value="10:00 - 20:00"/>
<div id="slider-time"></div><br>
这是一个例子:
答案 3 :(得分:0)
它应该是小时2&lt; 10和分钟2&lt; 10,而不是hours2.length&lt; 10和minutes2.length&lt; 10.这是对数值的评估,而不是字符串长度。