Question

是否有一种非常简单的方法可以在Python 3.x中访问http请求的直接文本/字节？类似于你从Telnet或类似的东西。我正在寻找一些我可以设置来监听端口，接受请求并直接阅读所遇到的内容。它不会定义它正在寻找POST或GET等，只是原始值：

样本值：

    GET /index.html/?=request HTTP/1.1
    Host: www.example.com
    User-Agent: Safari/4.0

Answer 1

我正在寻找的图书馆是here。我正在寻找的代码是：

import socketserver

class MyTCPHandler(socketserver.BaseRequestHandler):
    """
    The RequestHandler class for our server.

    It is instantiated once per connection to the server, and must
    override the handle() method to implement communication to the
    client.
    """

def handle(self):
    # self.request is the TCP socket connected to the client
    self.data = self.request.recv(1024).strip()
    print("{} wrote:".format(self.client_address[0]))
    print(self.data)
    # just send back the same data, but upper-cased
    self.request.sendall(self.data.upper())

if __name__ == "__main__":
    HOST, PORT = "localhost", 9999

    # Create the server, binding to localhost on port 9999
    server = socketserver.TCPServer((HOST, PORT), MyTCPHandler)

    # Activate the server; this will keep running until you
    # interrupt the program with Ctrl-C
    server.serve_forever()

用于访问http请求的超级简单Python 3.x库

1 个答案: