这是我的代码:
struct data {
char carReg[6];
char make[20], model[20], colour[20];
int numPrevOwners;
bool reserved;
float reserveAmount;
};
struct node {
struct data *element;
struct node *next;
};
在我的主要方法中,我有这个:
struct node *current, *aNode;
struct data *anElement, *newCar;
FILE *file;
file = fopen("d:car.dat", "r"); //open the file for reading
if (file == NULL) {
printf("Nothing found in this file.\n\n");
printf("\n");
}//end if
else {
//If it does exist, cars in file should be copied into the linked list
while(fread(&newCar, sizeof(struct data), 1, file)>0) {
aNode = (struct node *)malloc(sizeof(struct node));
anElement = (struct data *)malloc(sizeof(struct data));
strcpy(anElement->carReg ,newCar->carReg);
strcpy(anElement->make, newCar->make);
strcpy(anElement->model, newCar->model);
strcpy(anElement->colour, newCar->colour);
anElement->numPrevOwners = newCar->numPrevOwners;
anElement->reserved = newCar->reserved;
anElement->reserveAmount = newCar->reserveAmount;
if (aNode == NULL)
printf("Error - no space for the new node\n");
else { // add data part to the node
aNode->element = anElement;
aNode->next = NULL;
if (isEmpty())
{
front = aNode;
last = aNode;
}
else {
last->next = aNode;
last = aNode;
}
}
}//end while
printf("Cars in the system");
}//end else
我得到的错误信息是' carReg'尚未宣布,' make'尚未宣布等。
有人可以帮忙吗?
编辑 - 我已经更新了,它都编译但程序没有运行。它运行但是说title.exe已经停止运行。
答案 0 :(得分:0)
将struct data *anElement, *newCar;
替换为struct data *anElement; struct data newCar;
。
当前fread()
将sizeof(struct data)
字节读入指针(&newCar
是指针的地址),这可能不是您想要的(这也是经典的缓冲区溢出)
这也将修复您正在获取的错误,因为您尝试使用.
运算符通过指针访问struct成员。更改newCar
定义将解决此问题。