我下面的剧本非常适合显示生日,但它不会在生日日期显示生日,也会如何让这个人的生日当天离开?最后这个人将在这个生日那岁多了。
脚本是:
SELECT *
FROM DRIVERS e
WHERE 1 = CASE WHEN MONTH(GETDATE()) < MONTH(DATEADD(WK,
DATEDIFF(WK, 0, GETDATE())+1,-1))
THEN CASE WHEN MONTH(DOB) = MONTH(GETDATE()) + 1
AND DAY(DOB) >= 1
AND DAY(DOB) < DAY(DATEADD(WK,
DATEDIFF(WK, 0, GETDATE())
+ 1, -1)) THEN 1
WHEN MONTH(DOB) = MONTH(GETDATE())
AND DAY(DOB) >= DAY(GETDATE())
AND DAY(DOB) <= DAY(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))) THEN 1
ELSE 0 END
ELSE CASE WHEN MONTH(DOB) = MONTH(GETDATE())
AND DAY(DOB) >= DAY(GETDATE())+1
AND DAY(DOB) < DAY(DATEADD(WK,
DATEDIFF(WK, 0, GETDATE())
+ 1, -1)) THEN 1
ELSE 0
END
END
--// So I need the following:
--// 1. Show birthday on birthday date.
--// 2. Show Days Left until Birthday.
--// 3. Show Age of Person on upcoming birthday.
非常感谢您对此的任何帮助。
答案 0 :(得分:3)
尝试年龄:
CASE
WHEN DATEPART(DAYOFYEAR, DOB) < DATEPART(DAYOFYEAR, GETDATE())
THEN DATEDIFF(YEAR, DOB, GETDATE())
ELSE
DATEDIFF(YEAR, DOB, GETDATE())-1
END
这一天直到生日:
DATEDIFF(DAY, GETDATE(), DATEADD(YEAR,DATEDIFF(YEAR, DOB, GETDATE()), DOB))
可能需要进行一些调整,但在进行一些基本测试时会显示正确的结果。
答案 1 :(得分:0)
SELECT
FLOOR(DATEDIFF(DAY, GETDATE(), DATEADD(YEAR,DATEDIFF(YEAR, DOB, GETDATE()), DOB))) AS BDAYin
, FLOOR(DATEDIFF(dd,DOB, GETDATE()+7) / 365.25) AS AGEwillTurn
FROM DRIVERS
WHERE 1 = (FLOOR(DATEDIFF(dd,DOB,GETDATE()+7) / 365.25))-(FLOOR(DATEDIFF(dd,DOB,GETDATE()) / 365.25))