今年在MS SQL 2012中获得人员生日,剩余日期至Bday以及人员年龄

时间:2014-04-01 14:46:39

标签: sql sql-server

我下面的剧本非常适合显示生日,但它不会在生日日期显示生日,也会如何让这个人的生日当天离开?最后这个人将在这个生日那岁多了。

脚本是:

SELECT  *
FROM    DRIVERS e
WHERE   1 = CASE WHEN MONTH(GETDATE()) < MONTH(DATEADD(WK, 
                                       DATEDIFF(WK, 0, GETDATE())+1,-1))
THEN CASE WHEN MONTH(DOB) = MONTH(GETDATE()) + 1
            AND DAY(DOB) >= 1
            AND DAY(DOB) < DAY(DATEADD(WK,
                                 DATEDIFF(WK, 0, GETDATE())
                                       + 1, -1)) THEN 1 
    WHEN MONTH(DOB) = MONTH(GETDATE())
            AND DAY(DOB) >= DAY(GETDATE())
            AND DAY(DOB) <= DAY(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))) THEN 1

       ELSE 0 END

ELSE CASE WHEN MONTH(DOB) = MONTH(GETDATE())
            AND DAY(DOB) >= DAY(GETDATE())+1
            AND DAY(DOB) < DAY(DATEADD(WK,
                                 DATEDIFF(WK, 0, GETDATE())
                                       + 1, -1)) THEN 1
       ELSE 0
  END
END

--//    So I need the following:
--//    1. Show birthday on birthday date.
--//    2. Show Days Left until Birthday.
--//    3. Show Age of Person on upcoming birthday.

非常感谢您对此的任何帮助。

2 个答案:

答案 0 :(得分:3)

尝试年龄:

CASE 
  WHEN DATEPART(DAYOFYEAR, DOB) < DATEPART(DAYOFYEAR, GETDATE()) 
    THEN DATEDIFF(YEAR, DOB, GETDATE()) 
  ELSE 
    DATEDIFF(YEAR, DOB, GETDATE())-1 
END

这一天直到生日:

DATEDIFF(DAY, GETDATE(), DATEADD(YEAR,DATEDIFF(YEAR, DOB, GETDATE()), DOB))

可能需要进行一些调整,但在进行一些基本测试时会显示正确的结果。

答案 1 :(得分:0)

SELECT 
FLOOR(DATEDIFF(DAY, GETDATE(), DATEADD(YEAR,DATEDIFF(YEAR, DOB, GETDATE()), DOB))) AS BDAYin
, FLOOR(DATEDIFF(dd,DOB, GETDATE()+7) / 365.25) AS AGEwillTurn
FROM DRIVERS 
WHERE 1 = (FLOOR(DATEDIFF(dd,DOB,GETDATE()+7) / 365.25))-(FLOOR(DATEDIFF(dd,DOB,GETDATE()) / 365.25))