Question

    time stamp        meter name  parameter name        value
2014-02-18 18:58:00      1$SGP          A          415.7806091308594
2014-02-18 18:58:00      1$SGP           B          240.3373565673828
2014-02-18 18:58:01      2$SGP           A          393.191162109375
2014-02-18 18:58:02      2$SGP           B           50.10090637207031
2014-02-18 18:58:00      3$SGP           A          3484841472
2014-02-18 18:05:01      1$SGP           A          0
2014-02-18 17:58:01      1$SGP           A          0
2014-02-18 17:58:01      2$SGP           A          290
2014-02-18 17:58:01      2$SGP           D          0
2014-02-18 17:58:01      3$SGP           A          3061691904
2014-02-18 17:57:01      3$SGP           A          0
2014-02-18 17:57:02      3$SGP           B          0

找到两个连续时间戳的时间戳的差异，以及特定参数的每个单独仪表的值的差异。

预期输出：适用于18:58

01:00 1$SGP 415.7806091308594-0 01:00 2$SGP 393.191162109375-290 01:00 3$SGP 3484841472-3061691904

At，18：58 1 $ SGP，2 $ SGP和3 $ SGP抛出参数A的值。在17:58 1 $ SGP，2 $ SGP和3 $ SGP抛出参数A的值。休息要么所有的米都不在一起作为时间戳，如18:05 时间戳中可以忽略秒。所以，

01:00 1 $ SGP 415.7806091308594-0 01:00 2 $ SGP 393.191162109375-290 01:00 3 $ SGP 3484841472-3061691904

在MS SQL中提出查询时遇到问题。我也不熟悉使用date_format（）忽略mysql中的第二个转换方法。

Answer 1

这是示例表：

create table #t(ts datetime, mn char(5), pn char, val decimal (25,15));

insert #t values 
('2014-02-18 18:58:00',      '1$SGP',           'A',          415.7806091308594),
('2014-02-18 18:58:00',      '1$SGP',           'B',          240.3373565673828),
('2014-02-18 18:58:01',      '2$SGP',           'A',          393.191162109375),
('2014-02-18 18:58:02',      '2$SGP',           'B',           50.10090637207031),
('2014-02-18 18:58:00',      '3$SGP',           'A',          3484841472),
('2014-02-18 18:05:01',      '1$SGP',           'A',          0),
('2014-02-18 17:58:01',      '1$SGP',           'A',          0),
('2014-02-18 17:58:01',      '2$SGP',           'A',          290),
('2014-02-18 17:58:01',      '2$SGP',           'D',          0),
('2014-02-18 17:58:01',      '3$SGP',           'A',          3061691904),
('2014-02-18 17:57:01',      '3$SGP',           'A',          0),
('2014-02-18 17:57:02',      '3$SGP',           'B',          0);

以下是查询：

;with t as (
    select cast(ts as smalldatetime) as ts, mn, pn, val from #t
)
,
tt as (
    select ts from t
    group by ts
    having count(*) >= 3
),
ttt as (
    select *, row_number() over(partition by mn, pn order by ts desc) as rn
    from t where t.ts in (select tt.ts from tt)
)
select t1.ts, t1.mn, t1.val, t2.val
from ttt t1
inner join ttt t2 on t1.mn = t2.mn and t1.pn = t2.pn and t1.rn = 1 and t2.rn = 2;

MS SQL制定聚合和时间戳查询

1 个答案: