如何删除" null id ...条目(在发生异常后不要刷新会话)"

时间:2014-04-01 11:18:10

标签: java mysql hibernate flush

你好,我是php的web开发人员,最近是migto到javaEE。我在mysql中创建表。 这是头等舱:

@Entity
@Table(name = "first")
@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)   
@org.hibernate.annotations.Cache(usage = CacheConcurrencyStrategy.READ_WRITE,     inclu`enter code here`de = "all")
public class first extends second {

@OneToOne(cascade = CascadeType.ALL)
private second A;

。 。 。 这是我的第二堂课:

    @Entity
    @Table(name = "second", uniqueConstraints =
    @UniqueConstraint(columnNames = {"feildone", "feildtwo"}))
    public class second implements Serializable {
    @OneToOne(cascade = CascadeType.ALL, mappedBy = "first")
    public static final String FindOne = "findOne";
    @Id
    @GeneratedValue
    Integer id;
    private String feildtwo;
    private String feildone;
    @Temporal(javax.persistence.TemporalType.DATE)
    private Date createTime;
    @OneToMany(cascade = CascadeType.ALL)
    public List<Progress> progress = new ArrayList<>();
    private Integer num;

。 。

1 个答案:

答案 0 :(得分:1)

尝试自动生成您的ID,看看您是否面临同样的问题

 @Entity
        @Table(name = "second", uniqueConstraints =
        @UniqueConstraint(columnNames = {"feildone", "feildtwo"}))
        public class second implements Serializable {
        @OneToOne(cascade = CascadeType.ALL, mappedBy = "first")
        public static final String FindOne = "findOne";
        @Id
        @GeneratedValue(strategy = GenerationType.AUTO) // try to use auto generate id guess this might help
        Integer id;
        private String feildtwo;
        private String feildone;
        @Temporal(javax.persistence.TemporalType.DATE)
        private Date createTime;
        @OneToMany(cascade = CascadeType.ALL)
        public List<Progress> progress = new ArrayList<>();
        private Integer num;