Question

我不确定这是否可能我不知道我的表：tbchecked

[id] [name] [status]

001   john     present
001   john     present
001   john     absent
001   john     absent
001   john     leave
001   john     present
001   john     present
002   ace      present
002   ace      absent
002   ace      leave

...

有可能吗？在gridview1中输出如何查询？ 1-7不是在一周我想要计数1到xxx

[id] [name] [1]      [2]      [3]     [4]             [5]            [6]      [7]

001   john  present  present  absent  absent         leave          present  present
002   ace   present  absent   leave   ...

Answer 1

你可以试试这样的东西

DECLARE @TABLE TABLE
(  
ID INT,  
STATUS VARCHAR(10)
)

INSERT INTO @TABLE  
VALUES  (1, 'present'),
        (1, 'present'),
        (1, 'absent'),
        (1, 'absent'),
        (1, 'leave'),
        (1, 'present'),
        (1, 'present'),
        (2, 'present'),
        (2, 'absent'),
        (2, 'leave')


SELECT T1.ID,  
        STUFF(  
        (  
        SELECT ',' + T2.STATUS  
        FROM @TABLE T2  
        WHERE T1.ID = T2.ID  
        FOR XML PATH ('')  
        ),1,1,'')  
FROM @TABLE T1  
GROUP BY T1.ID

否则，您可以使用光标执行循环Declare Cursor

Answer 2

如果您的ID只有七行，那么这可能很有用。如果ID是任意随机数，那么你必须去对于动态sql或程序（如果可能）。

select ID,

SUBSTRING_INDEX(status,',','1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','2'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','3'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','4'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','5'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','6'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','7'),',','-1')

 from
(

SELECT  ID, group_concat(status) as status  

FROM TABLE T

GROUP BY ID

) A

sql查询和分组依据

2 个答案: