Question

public void onCreate(Bundle savedInstanceState) 
          {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.register_user_details);         
        btnNext = (Button) findViewById(R.id.btn_next);         
        btnNext.setOnClickListener(new View.OnClickListener()
               {
            public void onClick(View arg0){
                 Intent nxtpage = new Intent(getApplicationContext(),ChangePassword.class);

                edtName= (EditText) findViewById(R.id.edt_name);
                edtPhoneNumber= (EditText) findViewById(R.id.edt_phone_number);

                String Name=(String)edtName.getText().toString();
                String PhoneNumber=(String)edtPhoneNumber.getText().toString();

              //Create the bundle
                Bundle bundle = new Bundle();

                //Add your data to bundle
                bundle.putString(“Name”,Name);
                bundle.putString(“PhoneNumber”,PhoneNumber);

                //Add the bundle to the intent
                nxtpage.putExtras(bundle);

              //Fire that second activity
                 startActivity(nxtpage);
             }

  }
}
}

我试图捆绑此活动[register_user]的值，如姓名和电话号码，并发送到其他活动[注册]，但此处显示错误

                bundle.putString(“Name”,Name);
                bundle.putString(“PhoneNumber”,PhoneNumber);

错误：令牌上的语法错误，而是预期的ArgumentList

任何人都可以告诉我这是什么问题吗？

Answer 1

更改此

  bundle.putString(“Name”,Name);

到

  bundle.putString("Name",Name);

类似地

  bundle.putString("PhoneNumber",PhoneNumber);

您需要""而不是“”

Answer 2

这里是字符串名称和字符串PhoneNumber

之间发生名称冲突

请尝试

bundle.putString("name",Name);

bundle.putString("phonenumber",PhoneNumber);

捆绑活动内容以转移到android中的下一个Activity

2 个答案: