我正在构建一个程序,它将在两个Android设备之间发送/接收数据。 首先,我创建了一个客户端线程来发送数据
public void run() {
try {
//Create the datagram packet
byte[] buffer = message.getBytes();
InetAddress addr = InetAddress.getByName(address);
DatagramPacket packet = new DatagramPacket(buffer, buffer.length, addr, 5555);
//Create Datagram Socket
DatagramSocket socket = new DatagramSocket();
socket.setBroadcast(broadcast);
// send the packet
socket.send(packet); // i think that the problem was here
} catch (Exception e) {
e.printStackTrace();
Log.i("CTHREAD", "erreur");
}
在服务器线程上,我想收到这个数据包,所以我打开了一个datagramsocket来接收10个数据包。
public void run() {
try {
serverIP = getLocalIpAddress();
Log.v("addr", serverIP);
serverSocket = new ServerSocket(5001);
Log.v("socket", "created");
while(socketOk) { //boucle infini
Socket client = serverSocket.accept();
// Log.v("client", "received");
try {
DatagramSocket socket = new DatagramSocket(5556);
byte[] buf = new byte[1024]; //buffer
DatagramPacket packet = new DatagramPacket(buf, buf.length);
socket.receive(packet);
byte[] result = new byte[packet.getLength()];
System.arraycopy(packet.getData(), 0, result, 0, packet.getLength());
String msg = new String(result);
updateGui(msg, packet.getAddress());
} catch (Exception e) {
socketOk =false;
Log.v("ServerThread", "SocketOk =false");
}
}
}
catch (Exception e) {}
}
}
当我想发送消息时,我会收到一些警告,因此程序无法运行ClientThread。
at libcore.io.IoBridge.maybeThrowAfterSendto(IoBridge.java:506)
at libcore.io.IoBridge.sendto(IoBridge.java:475)
at java.net.DatagramSocket.send(DatagramSocket.java:284)
Caused by: libcore.io.ErrnoException: sendto failed: EACCES (Permission denied)
的Manifest.xml:
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE"></uses-permission>
<uses-permission android:name="android.permission.CHANGE_WIFI_STATE"></uses-permission>
<uses-permission android:name="android.permission.WAKE_LOCK"></uses-permission>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"></uses-permission>
<uses-permission android:name="android.permission.INTERNET" />
那么,问题是怎么回事?我怎么能解决它?
答案 0 :(得分:0)
您正在发送到5555端口但是您正在通过5556端口接收。
最好让服务器的DatagramSocket在整个过程中保持打开状态。