Question

我需要在操作栏中获取对项目的引用。我想在onCreate

中访问它

    int silent_mode = SupportFunctions.getSharedPreferenceInt(getApplicationContext(), getResources().getString(R.string.shared_preferences_name), "silent_mode", 0);
    Item item = // getItem?
    if (silent_mode == 1) {
        item.setIcon(getResources().getDrawable(R.drawable.ic_silent_mode_on));
    }
    else {
        item.setIcon(getResources().getDrawable(R.drawable.ic_silent_mode_off));
    }

有什么想法吗？

Answer 1

在onCreateOptionsMenu(Menu menu)中将菜单的引用存储在类级变量中。像这样：

Menu mnMenu;

public boolean onCreateOptionsMenu(Menu menu) {
    ....
    ....
    mnMenu = menu;
    return true;   
}

private void someMethod() {
    int silent_mode = SupportFunctions.getSharedPreferenceInt(getApplicationContext(),   getResources().getString(R.string.shared_preferences_name), "silent_mode", 0);
    MenuItem item = mnMenu.findItem(R.id.action) //R.id.action is the id of your MenuItem
    if (silent_mode == 1) {
        item.setIcon(getResources().getDrawable(R.drawable.ic_silent_mode_on));
    }
    else {
        item.setIcon(getResources().getDrawable(R.drawable.ic_silent_mode_off));
    }
}

Answer 2

在onCreateOptionsMenu()中完成工作，然后它将是可访问的：

    @Override
public boolean onCreateOptionsMenu(Menu menu) {

    ...


    MenuItem item = menu.findItem(R.id.YOUR_ID);
    int silent_mode = SupportFunctions.getSharedPreferenceInt(getApplicationContext(), getResources().getString(R.string.shared_preferences_name), "silent_mode", 0);
    if (silent_mode == 1) {
        item.setIcon(getResources().getDrawable(R.drawable.ic_silent_mode_on));
    }
    else {
        item.setIcon(getResources().getDrawable(R.drawable.ic_silent_mode_off));
    }

    return true;

}

获取actionbar项目？

2 个答案: