我正在制作一份啤酒杂志。当我想创建一个新的日记帐分录时,我在日记帐表中插入一行,其中包含我正在品尝的啤酒的ID。啤酒存放在单独的表中。将行插入日志表后,我想从beerData表中选择啤酒,以便在完成输入时将其显示给用户。我的插入工作正常,但我没有得到啤酒名称的任何回报。我尝试过几种不同的东西,但都不起作用。
<?php
if (isset( $_POST['newJournalEntry'] )) {
//Define POST Variables
$beerID = $_POST['id'];
//Create Record in Beer Journal
//SQL Query
$query = "INSERT INTO journal (beerID)
VALUES (:beerID);
SELECT beer FROM beerData
WHERE id = :beerID;";
//Prepare Query, Bind Parameters, Excute Query
$STH = $DBH->prepare($query);
$STH->bindParam(':beerID', $beerID);
$STH->execute();
$journal_id = $DBH->lastInsertId();
while($row = $STH->fetch(PDO::FETCH_ASSOC)){
echo $row['beer'];
}
} else {
echo "Test";
}
?>
第二次尝试:
<?php
if (isset( $_POST['newJournalEntry'] )) {
//Define POST Variables
$beerID = $_POST['id'];
//Create Record in Beer Journal
//SQL Query
$query = "INSERT INTO journal (beerID)
VALUES (:beerID)";
//Prepare Query, Bind Parameters, Execute Query
$STH = $DBH->prepare($query);
$STH->bindParam(':beerID', $beerID);
$STH->execute();
$journal_id = $DBH->lastInsertId();
//SQL Query
$query2 = "SELECT beer FROM beerData WHERE id = :beerID";
//Prepare Query, Bind Parameters, Execute Query
$STH2 = $DBH->prepare($query2);
$STH2->bindParam(':beerID', $beerID);
$STH2->execute();
while($row = $STH2->fetch(PDO::FETCH_ASSOC)){
echo $row['beer'];
}
} else {
echo "ELSE!!!";
}
?>