Question

我需要在以下代码中将p3.ID_miasta分配给@tabela，以便p3中的ID_miasta存储在表变量@tabela中。它说语法不正确附近＆＃39; =＆＃39;当我写@ tabela = p3.ID_miasta。你知道我能做到的其他方式吗？

create type cat as table
(id int)

declare @tabela cat;

with droga as
(
    select
        @tabela = p3.ID_miasta,
        p2.ID_miasta koniec,
        p1.ID_pociagu ostatni,
        ',' + cast(@poczatek as varchar(max)) + ',' + cast(p2.ID_miasta as varchar(max)) + ',' przesiadki,
        ',' + cast(p1.ID_pociagu as varchar(max)) + ',' pociagi
    from 
        postoje p1 
    inner join 
        postoje p2 on (p1.ID_pociagu = p2.ID_pociagu 
                       and p1.ID_miasta = @poczatek 
                       and p2.ID_miasta <> @poczatek) 
    inner join 
        postoje p3 on (p1.ID_pociagu = p3.ID_pociagu 
                       and (p3.odleglosc between (p1.odleglosc) and (p2.odleglosc)))

    union all

    -- (something not important)
)

Answer 1

两个CTE怎么样？而不是表变量将查询包装在CTE中并在第二个查询中使用它。

with tabela as
(
    select
        p3.ID_miasta,
        p2.ID_miasta koniec,
        p1.ID_pociagu ostatni,
        ',' + cast(@poczatek as varchar(max)) + ',' + cast(p2.ID_miasta as varchar(max)) + ',' przesiadki,
        ',' + cast(p1.ID_pociagu as varchar(max)) + ',' pociagi
    from 
        postoje p1 
    inner join 
        postoje p2 on (p1.ID_pociagu = p2.ID_pociagu 
                       and p1.ID_miasta = @poczatek 
                       and p2.ID_miasta <> @poczatek) 
    inner join 
        postoje p3 on (p1.ID_pociagu = p3.ID_pociagu 
                       and (p3.odleglosc between (p1.odleglosc) and (p2.odleglosc)))
)
, droga as
(
    select * from tabela

    union all

    -- another select using tabela
)

SQL - 将列分配给CTE中的表变量

1 个答案: